Answer:

They are dependent events.
Step-by-step explanation:
Given:
Number of $1 gift certificates = 2
Number of $2 gift certificates = 2
Number of $3 gift certificates = 10
To find:
Probability that a $1 gift certificate is selected, then a $3 and then a $2 certificate is selected = ?
Solution:
First of all, let us learn about the formula of probability of any event E:

Finding probability of choosing $1 gift certificate in the first turn:
Number of favorable cases or number of $1 gift certificates = 2
Total number of cases or total number gift certificates = 2 + 2 + 10 = 14
So, required probability = 
Finding probability of choosing $3 gift certificate in the 2nd turn:
Number of favorable cases or number of $1 gift certificates = 10
Now, one gift certificate is already chosen,
So, Total number of cases or total number gift certificates = 14 - 1 = 13
So, required probability = 
Finding probability of choosing $2 gift certificate in the 3rd turn:
Number of favorable cases or number of $2 gift certificates = 2
Now, two gift certificates is already chosen,
So, Total number of cases or total number gift certificates = 14 - 2 = 12
So, required probability = 
<em>Probability </em>that a $1 gift certificate is selected, then a $3 and then a $2 certificate is selected:

They are dependent events because <em>total number of cases and total number of favorable cases depend on the previous chosen gift certificate.</em>
<em></em>
<em>So, the answer is:</em>

They are dependent events.