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Harlamova29_29 [7]
3 years ago
6

Please help with #6 and #7 !!! desperate :(

Mathematics
1 answer:
babunello [35]3 years ago
4 0

Answer:

6. X=6

7. x=16 and y=11

Step-by-step explanation:

6. If UW bisects angles m<TUW=(13x-5) and m<WUV=(7x+31), find the value of x

To solve we need set both equations equal to each other

13x-5=7x+31

now we need to get both constants (numbers with out variables for example: 1) alone on one side and Variables alone on one side.

you want to look at the equation and see which one is easier to do first. I see that the most easiest way is to move -5 to the left side. to do so we need to add 5 to both sides.

13x-5=7x+31

+5 +5

13x=7x+3+5

Add 31 and 5 together since there both constants

31+5=36

13x=7x+36

now we need to move 7x to the right side. to do so we need to subtract 7x on both sides.

13x=7x+36

-7x -7x

13x-7x=36

now we need to subtract 7x from 13x since they are liked terms

13x-7x= 6x

6x=36

now we need to isolate x To do so we need to divide by 6 on both sides.

6x=36

--- ---

6 6

x=6

If m<DEG=(5x-4), m<DEF(7x-8)m< DEH=(9y+5) find the values of x and y

Since DEF and DEG are congruent we can add then together to get our x value

congruent angles add up to 180

5x-4+7x-8=180

add 5x and 7x

add -4 and -8

12x-12=180

ISOLATE X

Add 12 on both sides

12x=192

now we need to divide 12 on both sides

12x/12= x

192/12=16

x=16

DEF AND DEH are Vertical opposite meaning they add up to each other. they both have the same degree.

so

9y+5=7x-8

PLUG IN X=16

9y+5=7(16)-8

7*16=112

112-8 =104

9y+5=104

ISOLATE VARIABLE Y

subtract 5 on both sides

9y=99

now divide by 9 on both sides

9y/9=y

99/9=11

y=11

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Plzzzz I NEED help with 9 and 10 plzzzzz
jeyben [28]

<u><em>Question 9:</em></u>

\frac{20*(5)}{50}                    Simplify what is in the parenthesis

\frac{100}{50}                        Multiply 20 to 5

2                                            Divide 50 to 100

<u><em>*(Answer)*=</em></u> 2  

<u><em>Question 10:</em></u>

5+(18) ÷ 6                Simplify what is in the parenthesis      

5+3                                         Divide 6 to 18

8                                              Add 5 to 3

<u><em>*(Answer)*=</em></u> 8

Hope this helps

User who answered: <u><em>BangtanBoyScouts</em></u>






4 0
4 years ago
Diego’s family car holds 14 gallons of fuel. Each day the car uses 0.5 gallons of fuel. A warning light comes on when the remain
mixer [17]
His father can drive 25 days without the warning light
7 0
3 years ago
The first equation from the previous system of
icang [17]

Answer:

  (x, y) = (-5/3, 22/3)

Step-by-step explanation:

The graph and solution are shown below.

The solution is (-1 2/3, 7 1/3).

6 0
3 years ago
What number is missing? explanation please
-BARSIC- [3]
The missing number is 12

because the pattern is that the the numbers below and to the right of a number equals that number. ex: 3+4=7. so in order to find the missing number you have to do the opposite of addition, which is subtraction. (17-5=12)
8 0
3 years ago
Read 2 more answers
A lunch menu has a 4-piece lunch special which consists of a sandwich, soup, dessert and drink. They offer the following choices
ryzh [129]

Answer:

There are 160 possible 4-piece lunch special meal.

Step-by-step explanation:

The lunch menu has a 4-piece lunch special which consists of a sandwich, soup, dessert and drink.

The available options for the sandwiches, soups, desserts and drinks are:

Sandwich: chicken, cheese and tomato, tuna, ham and lettuce, turkey

Soup: tomato, chicken noodle, vegetable

Dessert: ice-cream, piece of cake

Drink: tea, coffee, Coke, Sprite

So, the number of options are:

n (Sandwich) = n (A) = 5

n (Soup) = n (B) = 4

n (Dessert) = n (C) = 2

n (Drink) = n (D) = 4

There are 5 ways to select a sandwich, 4 ways to select a soup, 2 ways to select a dessert and 4 ways to select a drink.

The total number of possible 4-piece lunch special is:

Total number of 4-piece lunch special = n (A) × n (B) × n (C) × n (D)

                                                                =5\times4\times2\times4\\=160\\

Thus, there are 160 possible 4-piece lunch special meal.

8 0
3 years ago
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