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3 years ago

The coordinates of points M,N, and P are ....

Mathematics

1 answer:

Rainbow [258]3 years ago

8 0

Answer:

(-1, -1) Let me know if the explanation didn't make sense.

Step-by-step explanation:

If we graph the three points we can see what looks like a quadrilateral's upper right portion, so we need a point in the lower left. This means M is only connected to N here and P is only connected to N. So we want to find the slope of these two lines.

MN is easy since their y values are the same, the slope is 0.

NP we just use the slope formula so (y2-y1)/(x2-x1) = (-1-3)/(5-4) = -4.

So now we want a line from point M with a slope of -4 to intersect with a line from point P with a slope of 0. To find these lines weuse point slope form for those two points. The formula for point slope form is y - y1 = m(x-x1)

y-3 = -4(x+2) -> y = -4x-5

y+1 = 0(x-5) -> y = -1

So now we want these two to intersect. We just set them equal to each other.

-1 = -4x -5 -> -1 = x

So this gives us our x value. Now we can plug that into either function to find the y value. This is super easy of we use y = -1 because all y values in this are -1, so the point Q is (-1, -1)

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If Rib-eye steaks are on sale for $8.52 per pound. Ms. Markum bought a 0.9-pound steak. How much did the steak cost?

Pepsi [2]

Answer: The steak costs $ 7.67.

Step-by-step explanation:

Given: Cost per pound of Rib-eye steaks = $8.52

Ms. Markum bought a 0.9-pound steak.

To find : cost of 0.9 pound steak =

Then cost of 0.9 pound steak = 0.9 x (Cost per pound of Rib-eye steaks )

= $ (0.9 x 8.52)

= $7.668 ≈ $ 7.67

Hence, the steak costs $ 7.67.

7 0

3 years ago

A golfball is hit from the ground with an initial velocity of 200 ft/sec. The horizontal distance that the golfball will travel,

algol13

Answer:

The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

Step-by-step explanation:

The formula from the maximum distance of a projectile with initial height h=0, is:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}$

Where $v_i$ is the initial velocity.

In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is $[0, \pi/2]$ . The critical points of the function are those who make $d'(\theta)=0$ :

$d(\theta)=\frac{v_i^2\sin(2\theta)}{g}\\d'(\theta)=\frac{v_i^2\cos(2\theta)}{g}*(2)\\d'(\theta)=\frac{2v_i^2\cos(2\theta)}{g}$

$d'(\theta)=0\\\frac{2v_i^2\cos(2\theta)}{g}=0\\\cos(2\theta)=0\\2\theta=\pi/2,3\pi/2,5\pi/2,...\\\theta=\pi/4,3\pi/4,5\pi/4,...$

The critical value inside the interval is $\pi/4$ .

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\d(\pi/4)=\frac{v_i^2sin(2(\pi/4))}{g}\\d(\pi/4)=\frac{v_i^2sin(\pi/2)}{g}\\d(\pi/4)=\frac{v_i^2(1)}{g}\\d(\pi/4)=\frac{(200)^2}{32}\\d(\pi/4)=\frac{40000}{32}\\d(\pi/4)=1250ft$

The second step is to find the values of the function at the endpoints of the interval:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\\theta=0\\d(0)=\frac{v_i^2sin(2(0))}{g}\\d(0)=\frac{v_i^2(0)}{g}=0ft\\\theta=\pi/2\\d(\pi/2)=\frac{v_i^2sin(2(\pi/2))}{g}\\d(\pi/2)=\frac{v_i^2sin(\pi)}{g}\\d(\pi/2)=\frac{v_i^2(0)}{g}=0ft$

The biggest value of f is gived by $\pi/4$ , therefore $\pi/4$ is the absolute maximum.

In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

4 0

3 years ago

NEED THIS ASAPWrite the standard form of the equation of each line given the slope and y-intercept

Mama L [17]

<em>Your first question is missing the y-intercept, so I am solving the 2nd question. You would still get your concept clear because the procedure to solve each of the questions is the same.</em>

Question 2

Answer:

The equation in the standard form is:

2/3x + y = -4

Please also check the attached graph.

Step-by-step explanation:

We know that the equation in the standard form is

Ax + By = C

where x and y are variables and A, B and C are constants

Given

Slope m = -2/3

y-intercept = -4

To determine

Write the equation in the standard form

We know that the slope-intercept form of the line equation

$y = mx+b$

where

m is the slope

b is the y-intercept

In our case:

Slope m = -2/3

y-intercept = -4

substituting m = -2/3 and y-intercept b = -4 in the slope-intercept of the line equation

y = mx+b

y = -2/3x + (-4)

y = -2/3x - 4

Writing the equation in the standard form

2/3x + y = -4

Therefore, the equation in the standard form is:

2/3x + y = -4

Please also check the attached graph.

4 0

3 years ago

Does anyone know this?

Y_Kistochka [10]

1/3 is equal to 33% because there are three different possibilties

8 0

3 years ago

1046.4 carried out to two decimal places

julia-pushkina [17]

Answer:

1046

Step-by-step explanation:

7 0

3 years ago