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ivanzaharov [21]
3 years ago
7

Marked price of an item is 4000, what will be it's selling price having 20% discount and 10% vat.​

Mathematics
2 answers:
lara [203]3 years ago
4 0

Answer:

<em><u>I</u></em><em><u> </u></em><em><u>HOPE</u></em><em><u> </u></em><em><u>IT</u></em><em><u> </u></em><em><u>WILL</u></em><em><u> </u></em><em><u>HELP</u></em><em><u> </u></em>

<em><u>EXPLANATION</u></em><em><u> </u></em><em><u>IS</u></em><em><u> </u></em><em><u>IN</u></em><em><u> </u></em><em><u>THE</u></em><em><u> </u></em><em><u>PHOTO</u></em><em><u> </u></em><em><u>.</u></em>

gizmo_the_mogwai [7]3 years ago
4 0
Another way to do it is by

Multiplying the original value by the discounted percent, the percent taxed but add one to it.

(4,000)(.80)(1+10/100)= 3,520

4000 is the original value
.80 is the value of the item with 20% off
1.1 gives value after tax, adding the one allows you to see the value of the item after tax.




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Its going to be obviously D

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  1. x² = 16 y
  2. x = 0
  3. (x + 4)² = 2/3 (y - 2)
  4. Gayle identifies that the vertex of the parabola is <u>(3, -1)</u> . The parabola opens <u>right</u>, and the focus is <u>3 </u>units away from the vertex. The directrix is <u>6 </u>units from the focus. The focus is the point <u>(6, -1)</u>. The directrix of the equation is <u>x = 0.</u>
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Step-by-step explanation:

1. First figure

We plot the parabola as given in the attached diagram.

As it is facing upwards, the equation goes as x² = 4py

where, p = 4 (refer the attached diagram)

x² = 4py

x² = 4 (4) y

∴, standard form of parabola is x² = 16 y

2. Second figure

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Comparing the given equation with the standard form

(y - k)² = 4p (x - h)

Now from this equation we get to know that

h = 1

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3x² + 24x - 2y + 52 = 0

3x² + 24x = 2y - 52

3 (x² + 8x) = 2 (y - 26)

(x² + 8x) = 2 (y - 26) / 3

Adding 16 on both sides,

x² + 8x + 16 = 2 (y - 26) / 3 + 16

(x + 4)² = 2/3 y - 52/3 + 16

(x + 4)² = 2/3 y - 4/3

(x + 4)² = 2/3 (y - 2)

4. Fourth figure

(y + 1)² = 12 (x - 3)

Comparing the given equation with the standard form

(y - k)² = 4p (x - h)

Now from this equation we get to know that

k = -1

h = 3

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Gayle identifies that the vertex of the parabola is <u>(3, -1)</u> . The parabola opens <u>right</u>, and the focus is <u>3 </u>units away from the vertex. The directrix is <u>6 </u>units from the focus. The focus is the point <u>(6, -1)</u>. The directrix of the equation is <u>x = 0.</u>

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Focus = (2, 6)

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Therefore, it follows the standard form

(y - k)² = 4p (x - h)

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Focus is given by (h + p, k) = (2, 6)

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2 - p - p = 4

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p = -1

Hence, h = 3

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(y - 6)² = 4p (x - 3)

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