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weeeeeb [17]
3 years ago
5

Easy question in photo

Mathematics
2 answers:
Alex3 years ago
8 0

<em>Answer:</em>

<em>14</em>

<em>Step-by-step explanation:</em>

<em>always subtract the highest number from the lowest and I believe that is your range</em>

olga_2 [115]3 years ago
3 0

Answer:

14

Step-by-step explanation:

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Form a paragraph proof for the following. Make sure you include all the
timama [110]

Answer:

Line BD is Congruent to Line BD due to the Reflexive property. Angle Bad is congruent to angle BCD because of the third angle theorem therefore triangle ABD is congruent to triangle CBD because all angles and sides are congruent

I don't know if that will satisfy your teacher because some prefer different things but that leaves no ground to be inferred and explains everything word for word.

8 0
3 years ago
Look at this graph:
Sladkaya [172]

Answer:

2

Step-by-step explanation:

slope=rise/run=20/10=2/1=2.

4 0
3 years ago
PLEASE HELP DUE TODAY!!!!!
Nezavi [6.7K]
It’s F


How to do it: 4-2=2
2 to the second is 4
4+4 =8
8-1=7.

Hope this helps ;)
6 0
3 years ago
Read 2 more answers
What is the equation of the line with m = 6 that goes through the point (1, 4)?
Rzqust [24]
Answer: B) y-4=6(x-1)

Substitute the point into each equation

A: y-4=6(x+1)

4-4=6(1+1)

4-4=6+6

0=12

This is false so it is not the answer

B: y-4=6(x-1)

4-4=6(1-1)

4-4=6-6

0=0

This is true so this is the answer, but I will continue solving just to check

C: y+4=6(x-1)

4+4=6(1-1)

4+4=6-6

8=0

This is false so it is not the answer

D: y+4=6(x+1)

4+4=6(1+1)

4+4=6+6

8=12
This is not true so it is not the answer

Your answer becomes b, the only true equation! Hope this helps comment below for more questions :)
8 0
3 years ago
Read 2 more answers
Given that Cos0=5/13,find a)Tan0,b)Sin0,c)Sec0,d)Co sec0,e)Cot0,​
qwelly [4]

cos θ = Adjacent/ hypotenuse

cosθ= 5/13

a²+b²= c²

a² + 5² = 13²

a² = 13² - 5²

a² = 144

a=√144

a= 12

<u>a</u> is the opposite = 12

<u>b</u> is the Adjacent = 5

<u>c</u> is the hypotenuse = 13

a) tan θ= opposite/Adjacent

tan θ = 12/5

b) sin θ= opposite/ hypotenuse

sinθ= 12/13

C) sec θ= hypotenuse / Adjacent

sec θ= 13/5

d) cscθ= hypotenuse /opposite

cscθ= 13/12

e) cotθ=Adjacent/ opposite

cotθ= 5/12

3 0
2 years ago
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