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3 years ago

PLZ HALP I NEED HALP YA IM TALKING TO YOU (25 points)

Mathematics

1 answer:

pashok25 [27]3 years ago

5 0

answer:

b + 3 + 6c = no

-30 - 24z = no

27n + 66p = yes

36 - 9j + 6k = yes

-- if correct, please mark the brainliest and click the thanks button :)

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Compare and contrast perpendicular bisected and altitude

elena55 [62]

A perpendicular bisector forms two right angles and splits the line in two equal parts.

The altitude does create two right angles, but doesn't have to create two equal parts.

6 0

3 years ago

Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the proporti

hodyreva [135]

Answer:

The sample size n = 4225

Step-by-step explanation:

We will use maximum error formula = $\frac{z_{a} S.D}{\sqrt{n} }$

but we will find sample size "n"

$\sqrt{n} = \frac{z_{a} S.D}{maximum error}$

Squaring on both sides , we get

$n = (\frac{z_{a} S.D}{maximum error})^2$

Given 99% confidence interval (z value) = 2.56

given maximum error = 0.02

$n = (\frac{z_{a} p(1-p)}{maximum error})^2$

n≤ $(\frac{2.56X\frac{1}{2} }{0.02}) ^{2}$ ( here S.D = p(1-p) ≤ 1/2

on simplification , we get n = 4225

Conclusion:

The sample size of two samples is n = 4225

verification:-

We will use maximum error formula = $\frac{z_{a} S.D}{\sqrt{n} }$ = $\frac{2.56 1/2}{\ \sqrt{4225} }$ = 0.0196

substitute all values and simplify we get maximum error is 0.02

4 0

3 years ago

Which expression is equivalent to

noname [10]

Answer:

3/5 m^2 n^3

Step-by-step explanation:

√225 = 15

√625 = 25

√m^4 = m^2

√n^6 = n^3

Put it all together and you get 15/25 m^2 n^3

Simplify 15/25 to 3/5

4 0

3 years ago

Read 2 more answers

In a particular course, it was determined that only 70% of the students attend class on Fridays. From past data it was noted tha

siniylev [52]

Answer: Probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

Step-by-step explanation:

Since we have given that

Probability that students attend class on Fridays = 70% = 0.7

Probability that who went to class on Fridays would pass the course = 95% = 0.95

Probability that who did not go to class on Fridays would passed the course = 10% = 0.10

Let A be the event students passed the course.

Let E be the event that students attend the class on Fridays.

Let F be the event that students who did not attend the class on Fridays.

Here, P(E) = 0.70 and P(F) = 1-0.70 = 0.30

P(A|E) = 0.95, P(A|F) = 0.10

We need to find the probability that they did not attend on Fridays.

We would use "Bayes theorem":

$P(F\mid A)=\dfrac{P(F).P(A\mid F)}{P(E).P(A\mid E)+P(F).P(A\mid F)}\\\\P(F\mid A)=\dfrac{0.30\times 0.10}{0.70\times 0.95+0.30\times 0.10}\\\\P(F\mid A)=\dfrac{0.03}{0.695}=0.043$

Hence, probability that students who did not attend the class on Fridays given that they passed the course is 0.043.

8 0

3 years ago

Draw a figure with the given perimeter. 6 units

erica [24]

We have to draw a figure with a perimeter 6 units. If we want to draw a rectangle it can`t be a 3 by 2 because it has a perimeter 2*2 + 2*3 = 4 + 6 = 10 units. It must be a 2 by 1 rectangle ( 2*2 + 2*1 = 4 + 2 = 6 units ).

6 0

4 years ago