The fuel economy of the vehicle at 65 mph can be determined using the given equation. The fuel economy, y, can be solved by substituting the car's speed, x, to 65. Doing this, will result to y = 36.5988. Thus, the correct answer among the choices is that the fuel economy of the vehicle at 65 mph is about 37 mpg.
Answer:
There are 10 blocks in a row (section). There are 6 rows (sections).
1.
A. If each block has a value of one, what is the value for a section of blocks?
<h2>
10</h2>
There are 10 blocks in a section. 10 * 1 = 10
B. What is the total value of all the blocks, write an equation?
<h2>60</h2>
There are 6 sections. There are 10 blocks in a section. 6 * 10 * 1 = 60
2.
A. If each block has a value of ten, what is the value for a section of blocks?
<h2> 100</h2>
There are 10 blocks in a section. 10 * 10 = 100
B. What is the total value of all the blocks, write an equation?
<h2>600</h2>
There are 6 sections. There are 10 blocks in a section. 60 * 10 * 10 = 600
It’s unsolvable with out more context. What’s the rest of the problem.
Answer:
-1
Step-by-step explanation:
Answer:
After 19 months,value in the account will reach $3700
Step-by-step explanation:
The value of a savings account f(t) in terms of t ( number of months since account opening) is given as ![\[3,500(1.003)^{t}\]](https://tex.z-dn.net/?f=%5C%5B3%2C500%281.003%29%5E%7Bt%7D%5C%5D)
We need to determine the value of t when f(t)>=3700
Expressing it in equation form,
![\[3,500(1.003)^{t} >= 3700\]](https://tex.z-dn.net/?f=%5C%5B3%2C500%281.003%29%5E%7Bt%7D%20%3E%3D%203700%5C%5D)
![\[=>(1.003)^{t} >= \frac{3700}{3500}\]](https://tex.z-dn.net/?f=%5C%5B%3D%3E%281.003%29%5E%7Bt%7D%20%3E%3D%20%5Cfrac%7B3700%7D%7B3500%7D%5C%5D)
![\[=>(1.003)^{t} >= 1.057\]](https://tex.z-dn.net/?f=%5C%5B%3D%3E%281.003%29%5E%7Bt%7D%20%3E%3D%201.057%5C%5D)
Taking log of both sides,
![\[=>t * log(1.003) >= log(1.057)\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Et%20%2A%20log%281.003%29%20%3E%3D%20log%281.057%29%5C%5D)
![\[=>t >= \frac{log(1.057)}{log(1.003)}\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Et%20%3E%3D%20%5Cfrac%7Blog%281.057%29%7D%7Blog%281.003%29%7D%5C%5D)
![\[=>t >= 18.51\]](https://tex.z-dn.net/?f=%5C%5B%3D%3Et%20%3E%3D%2018.51%5C%5D)
So t = 19.
