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dsp73
4 years ago
7

10 X 10 X 10 Can someone help

Mathematics
1 answer:
svp [43]4 years ago
6 0

Answer:

1000

Step-by-step explanation:

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Sylvester says that 0.000002015 written in scientific notation is 2.015 x 10 by the power of 6. Do you agree with him? Explain w
Marrrta [24]

Answer:

0.000002015 is not equal to 2.015x10^6

Step-by-step explanation:

When a power of 10 is positive the dot must be moved to the right, and when the power of 10 is negative, the dot must be moved to the left.

For example 50.000x10^3=50000 and 45.00x10^{-3}=0.045

So

2.015x10^6=2,015,000

wich is clearly not equal to 0.000002015

the correct scientific notation for 0.000002015 must be:

2.015x10^{-6}

With a negative in the power of 10, referring to a small quantity.

3 0
3 years ago
What is the volume of the cylinder shown below?
seraphim [82]

There is no diagram tho

3 0
3 years ago
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Help again lol don’t feel like thinking
Alexxandr [17]

Answer:

point O, it is located on (-4.5, -7)

6 0
3 years ago
tina has 50 coins, all dimes and quarters. the value of the coins is $7.10. write a system of equations to determine how many di
Sliva [168]

Answer:

A) D + Q = 50

B) .10D + .25Q = 7.10

We multiply A) by -.10

A) -.10D - .10Q = -5 then adding this to B)

B) .10D + .25Q = 7.10

.15Q = 2.10

Quarters = 14 = 3.50

Dimes = 36 = 3.60


Step-by-step explanation:


7 0
3 years ago
In terms of the trigonometric ratios for ΔABD, what is the length of line segment BD?
erica [24]

In terms of the trigonometric ratios for ΔABD, what is the length of line segment BD?

Answer:

BD = c*sin(A)

BD = c*cos(B)

BD = b*tan(A)

Step-by-step explanation:

∆ABD is a right triangle.

Recall: trigonometric ratios of any right triangle can easily be understood or remembered with the acronym, SOHCAHTOA.

SOH => sin(θ) = opposite/hypotenuse

CAH => Cos(θ) = adjacent/hypotenuse

TOA = tan(θ) = opposite/adjacent

Thus, the length of segment BD, in terms of trigonometric ratios for ∆ABD can be done as follows:

Let BD = x

AB = c

AD = b

=>The sine ratio for the length of line segment BD = x, using SOH.

θ = A

Opposite = DB = x

hypotenuse = AB = c

sin(A) = \frac{x}{c}

Make x the subject of formula.

c*sin(A) = x

BD = x = c*sin(A)

=>The Cosine ratio for the length of line segment BD = x, using CAH

θ = B

Adjacent = DB = x

hypotenuse = AB = c

cos(B) = \frac{x}{c}

Make x the subject of formula.

c*cos(B) = x

BD = x = c*cos(B)

=>The Tangent ratio for the length of line segment BD = x, using TOA

θ = A

Adjacent = DB = x

hypotenuse = AD = b

tan(A) = \frac{x}{b}

Make x the subject of formula.

b*tan(A) = x

BD = x = b*tan(A)

5 0
4 years ago
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