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Olegator [25]
3 years ago
5

A bakery sold 115 cupcakes in one day. The head baker predicted he would sell 95 cupcakes that day. What was the percent error o

f the baker's prediction?
Mathematics
1 answer:
Brut [27]3 years ago
5 0
It was about 17.4% 
======================================================================

% error=
actual value-estimated value 
Then divide that by actual value
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Find the probability for one roll of a number cube.<br><br> P(number greater than or equal to 7)
Alik [6]

Answer:

Step-by-step explanation:

there is no number of 7 or greater.

P(≥7)=0/6=0

6 0
3 years ago
What are the opposites of 9, −2.7, 3.35, and 6
azamat

Answer:

Step-by-step explanation: -9,2,-7,-3,-35, and -6

6 0
3 years ago
Write the inverse of f(x)=x2+4
Over [174]
F(x) = x² + 4
y = x² + 4

First, I reverse the equation to be
x² + 4 = y

Second, we need only x to remain on the left side and we need to move the others to the right side
x² + 4 = y
x² = y - 4
x = √(y - 4)

Last, change into invers function
f⁻¹(x) = √(x - 4)
7 0
4 years ago
Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,
torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

y=6x^2+14x

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

\frac{dy}{dx}=12x+14

We know that length of curve

s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx

We have a=-2 and b=1

Using the formula

Length of curve=s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

dt=12dx

dx=\frac{1}{12}dt

Length of curve=s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt

We know that

\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C

By using the formula

Length of curve=s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}

Length of curve=s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}

Length of curve=s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})

Length of curve=s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})

Length of curve=s=32.66

5 0
3 years ago
Will give brainliest to right answer Homies
BigorU [14]

Answer:

C :) hope it helps

Step-by-step explanation:

3 0
3 years ago
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