How much greater is the area of a circle with a radius of 6.1 inches than the area of a square with a side length of 4 inches?
1 answer:
Answer:
The area of the circle is 100.8394 square inches greater than the area of the square.
Step-by-step explanation:
Given:
The radius of the circle 6.1 inches
side of the square= 4 inches
Finding the area of the circle
Area of the circle=
=
= 116.8394 square inches
Area of the square= side*side
The area of the circle is 100.8394 square inches greater than the area of the square.
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Answer:
No, yes, yes
(-28,-11) and (8.7)
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Step-by-step explanation:
Given that a line in two dimension is parametrized by
a) If t is non negative, then (-28,-11) cannot lie on that part
(-28,-11) No because t =-5
(8,7) yes because t =1
(26,16) yes because t = 4
b) when t lies between -2 and 1
we have left end point as
(-10,-2) is left end point
Right end point is when t =1 i.e.
(8,7)
c) when the points should be above x axis, y should be non negative
i.e.
So t should lie in the interval
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