How much greater is the area of a circle with a radius of 6.1 inches than the area of a square with a side length of 4 inches?
1 answer:
Answer:
The area of the circle is 100.8394 square inches greater than the area of the square.
Step-by-step explanation:
Given:
The radius of the circle 6.1 inches
side of the square= 4 inches
Finding the area of the circle
Area of the circle=
=
= 116.8394 square inches
Area of the square= side*side
The area of the circle is 100.8394 square inches greater than the area of the square.
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The value of x is 77 cm which will make the triangles similar by SSS similarity theorem
Given length of the three sides of one triangle are 35 , 20 and 20
and length of the three sides of another triangle are x, 44,44
We need to find the values of x by using SSS Similarity theorem
We know that triangles are are similar by side - side - side similarity creation and hence the sides are in the same ratio
As both the triangles are isosceles triangles
Therefore ,
x/35 = 44/20=44/20 (Using ratio)
Solving the equation we get
x=44*35/20
x= 77
Hence the value of x is 77cm
Learn more about similarity of triangles here brainly.com/question/14285697
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