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seraphim [82]
2 years ago
6

How much greater is the area of a circle with a radius of 6.1 inches than the area of a square with a side length of 4 inches?

Mathematics
1 answer:
umka2103 [35]2 years ago
4 0

Answer:

The area of the circle is 100.8394 square inches greater than the area of the square.

Step-by-step explanation:

Given:

The radius of the circle 6.1 inches

 side of the square= 4 inches

Finding the area of the circle

Area of the circle= \pi r^2

                           =\pi *6.1*6.1

                          =3.14*6.1*6.1

                          = 116.8394 square inches

Area of the square= side*side

                               =4*4\\                                 =16 square inches

116.8394-16=100.8394

The area of the circle is 100.8394 square inches greater than the area of the square.

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Sergeu [11.5K]

Good morning ☕️

Answer:

<h2>168 ft²</h2>

Step-by-step explanation:

the surface area of the triangular prism =

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the base’s area =

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the lateral area =

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finally,

the surface area of the triangular prism = 24 + 144 = 168

___________________________________________

:)

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2 years ago
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Answer:

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Step-by-step explanation:

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