Question

How much greater is the area of a circle with a radius of 6.1 inches than the area of a square with a side length of 4 inches?

Answer 1

Answer:

The area of the circle is 100.8394 square inches greater than the area of the square.

Step-by-step explanation:

Given:

The radius of the circle 6.1 inches

 side of the square= 4 inches

Finding the area of the circle

Area of the circle= $\pi r^2$

                           =$\pi *6.1*6.1$

                          $=3.14*6.1*6.1$

                          = 116.8394 square inches

Area of the square= side*side

                               $=4*4\\ =16 square inches$

$116.8394-16=100.8394$

The area of the circle is 100.8394 square inches greater than the area of the square.