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anzhelika [568]
3 years ago
10

7 + 6(w +-6) vbdrufbhjf

Mathematics
1 answer:
ZanzabumX [31]3 years ago
8 0

Answer:

6w - 29

Step-by-step explanation:

You might be interested in
Number 26.
Natasha_Volkova [10]
B.

This is because when you substitute y-2 in for x, you get y=(y-2)+2.
Then the twos would cancel out, leaving you with y=y which would make an infinite number of solutions for y.
3 0
3 years ago
Given: -7x<-21 choose the solution set
Ahat [919]

Answer:

x > 3

Step-by-step explanation:

The only thing you need to do is just divide both sides by -7

-7x/-7<-21/-7

x>3

I hope this helped!! Good luck (:

6 0
2 years ago
My Homework Mr Thompson please help!!
Nady [450]

Answers:

  1. C) Factored form
  2. C) Standard form
  3. D) The y intercept is -8
  4. B) Two solutions: x = -5 or x = 5
  5. B) Apply square root to both sides

=========================================

Explanations:

  • For problems 1 and 2, there's not much to say other than you'll just have to memorize those terms. Standard form is ax^2+bx+c in general. The exponents count down 2,1,0. Factored form is where we have two or more factors multiplying with each other. Think of something like 21 = 7*3 showing that 7 and 3 are factors of 21.
  • For problem 3, the y intercept is the last value. It's the constant value. Plug in x = 0 and you'll get y = -8 as a result. The y intercept always occurs when x = 0.
  • In problem 4, we apply the square root to both sides to get x = -5 or x = 5. The plus or minus is needed. This is because (-5)^2 = 25.
  • In problem 5, we apply the square root to both sides to undo the squaring operation.
4 0
3 years ago
Write an equation that represents the line. (-3,-6) and (2,-2) use exact numbers
Ilia_Sergeevich [38]

Given:

The line passes through (-3,-6) and (2,-2).

To find:

The equation of line.

Solution:

If a line passes through two points (x_1,y_1)\text{ and }(x_2,y_2), then the equation of line is

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

The line passes through (-3,-6) and (2,-2). So, the equation of line is

y-(-6)=\dfrac{-2-(-6)}{2-(-3)}(x-(-3))

y+6=\dfrac{-2+6}{2+3}(x+3)

y+6=\dfrac{4}{5}(x+3)

y+6=\dfrac{4}{5}(x)+\dfrac{4}{5}(3)

Subtract 6 from both sides.

y=\dfrac{4}{5}(x)+\dfrac{12}{5}-6

y=\dfrac{4}{5}(x)+\dfrac{12-30}{5}

y=\dfrac{4}{5}(x)+\dfrac{-18}{5}

y=\dfrac{4}{5}(x)-\dfrac{18}{5}

Therefore, the equation of line is y=\dfrac{4}{5}(x)-\dfrac{18}{5}.

3 0
3 years ago
Which of the following is the graph of y=sqr root -x-3
Elan Coil [88]

Answer:

The graph in the attached figure

see the explanation

Step-by-step explanation:

we have

y=\sqrt{-x-3}

we know that

The radicand must be greater than or equal to zero

so

(-x-3)\geq 0

solve for x

Adds 3 both sides

-x\geq 0+3

-x\geq 3

Multiply by -1 both sides

Remember that, when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

x\leq -3

so

The domain of the function is the interval (-∞,-3]

For x=-3 ---> the value of y=0

The range is the interval {0,∞)

therefore

The graph in the attached figure

3 0
3 years ago
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