Question

How do I prove that 5^31-5^29 is divisible by 100 in the form of ___*100?

Answer 1

You can pull a common factor from both terms:

$5^{31}-5^{29}=5^{29+2}-5^{29}=5^{29}(5^2-1)=24\cdot5^{29}$

Next, pull a factor of 4 from 24, and 25 from the power of 5; since 100 = 25*4, we have

$5^{31}-5^{29}=\underbrace{5^{27}\cdot6}\cdot100$