The numbers are "x" and "y", therefore, we suggest this system of equations:
x-y=14
xy=1800
We can solve by substitution method.
x=14+y
(14+y)y=1800
14y+y²=1800
y²+14y-1800=0
Now, we solve this square equation:
y=[-14⁺₋√(196+7200)] / 2=(-14⁺₋86)/2
We have two solutions:
y₁=(-14-86)/2=-50 ⇒x=14+y=14-50=-36
y₂=(-14+86)/2=36 ⇒x=14+y=14+36=50
Answer: we have two solutions:
Solution1: The first number is -36 and the other number is -50
Soltuion2: The first number is 50 and the other number is 36
Let the consecutive integers be x and x+1.
Then,
x + (x + 1) = 23
=> x + x + 1 = 23
=> 2x + 1 = 23
=> 2x = 23 - 1
=> 2x = 22
=> x = 22/2
=> x = 11
So, the integers are:
x = 11
and x + 1 = 11 + 1 = 12
So, the consecutive integers are 11 and 12.
Answer:
I dont see nun
Step-by-step explanation:
10x+20y=540
x+y=34
y=34-x
Plug in (34-x) for y:
10x+20(34-x)=540
10x+680-20x=540
-10x=-140
10x=140
x=14
There were 14 ten cent coins and 20 20 cent coins
Answer:
Step-by-step explanation:
