Answer:
Step-by-step explanation:
Its actually -6.9
Sounds as tho' you have an isosceles triangle (a triangle with 2 equal sides). If this triangle is also a right triangle (with one 90-degree angle), then the side lengths MUST satisfy the Pythagorean Theorem.
Let's see whether they do.
8^2 + 8^2 = 11^2 ???
64 + 64 = 121? NO. This is not a right triangle.
If you really do have 2 sides that are both of length 8, and you really do have a right triangle, then:
8^2 + 8^2 = d^2, where d=hypotenuse. Then 64+64 = d^2, and
d = sqrt(128) = sqrt(8*16) = 4sqrt(8) = 4*2*sqrt(2) = 8sqrt(2) = 11.3.
11 is close to 11.3, but still, this triangle cannot really have 2 sides of length 8 and one side of length 11.
Answer:
P1 = P2 - ma*t
Step-by-step explanation:
ma= P2-P1/t
we multiply by t both sides of the equation
ma*t = (P2 - P1)*t/t
ma*t = P2 - P1
we sum by P1 both sides of the equation:
P1 +ma*t = P2 - P1 +P1
We ave:
P1 + ma*t = P2
we subtract by ma*t both sides of the equation:
P1 + ma*t -ma*t = P2 - ma*t
finally we have:
P1 = P2 - ma*t
