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EastWind [94]
3 years ago
15

A heron can travel an average of 400 km in 10h. What is the rate of change of distance?

Mathematics
2 answers:
rusak2 [61]3 years ago
8 0

Answer:

40 km/h

Step-by-step explanation:

rate of change of distance = speed

speed = distance/time

speed = (400 km)/(10 h)

speed = 40 km/h

Anvisha [2.4K]3 years ago
4 0

Rate of change of distance is also known as speed.

Given,

Distance (s) = 400km = 400 × 1000m = 400,000m

Time (t) = 10h = 10 × 3600s = 36,000s

We know that,

Speed (v) = Distance/Time

=> v =  \frac{s}{t}  \\ => v =  \frac{400000m}{36000s}  \\ => v =  \frac{400m}{36s}  \\ => v =  \frac{100m}{9s}  \\ => v =  \frac{100}{9}m {s}^{ - 2}   \\

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Calculate the sum of the multiples of 4 from 0 to 1000
allochka39001 [22]

Answer:

sum is 125,500

sum in summation notation is \sum\limits_{n=0}^n a+nd= (2a+(n-1)d)n/2

Step-by-step explanation:

This problem can be solved using concept of arithmetic progression.

The sum of n term terms in arithmetic progression is given by

sum = (2a+(n-1)d)n/2

where

a is the first term

d is the common difference of arithmetic progression

_____________________________________________________

in the problem

series is multiple of 4 starting from 4 ending at 1000

so series will look like

series: 0,4,8,12,16..................1000

a is first term so

here a is 0

lets find d the common difference

common difference is given by nth term - (n-1)th term

lets take nth term as 8

so (n-1)th term = 4

Thus,

d = 8-4 = 4

d  can also be seen 4 intuitively as series is multiple of four.

_____________________________________________

let calculate value of n

we have last term as 1000

Nth term can be described

Nth term = 0+(n-1)d

1000 =   (n-1)4

=> 1000 = 4n -4

=> 1000 + 4= 4n

=> n = 1004/4 = 251

_____________________________________

now we have

n = 1000

a = 0

d = 4

so we can calculate sum of the series by using formula given above

sum = (2a+(n-1)d)n/2

       = (2*0 + (251-1)4)251/2

       = (250*4)251/2

     = 1000*251/2 = 500*251 = 125,500

Thus, sum is 125,500

sum in summation notation is \sum\limits_{n=0}^n a+nd= (2a+(n-1)d)n/2

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