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EastWind [94]
3 years ago
15

A heron can travel an average of 400 km in 10h. What is the rate of change of distance?

Mathematics
2 answers:
rusak2 [61]3 years ago
8 0

Answer:

40 km/h

Step-by-step explanation:

rate of change of distance = speed

speed = distance/time

speed = (400 km)/(10 h)

speed = 40 km/h

Anvisha [2.4K]3 years ago
4 0

Rate of change of distance is also known as speed.

Given,

Distance (s) = 400km = 400 × 1000m = 400,000m

Time (t) = 10h = 10 × 3600s = 36,000s

We know that,

Speed (v) = Distance/Time

=> v =  \frac{s}{t}  \\ => v =  \frac{400000m}{36000s}  \\ => v =  \frac{400m}{36s}  \\ => v =  \frac{100m}{9s}  \\ => v =  \frac{100}{9}m {s}^{ - 2}   \\

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d

Step-by-step explanation:

4 0
3 years ago
A box of 80 coins, consisting of only nickels and dimes, is worth 7 dollars and 80 cents. Find the number of nickels.
Zepler [3.9K]
4 nickles
Explanation:
80=N+D
7.80=0.05N + 0.1D

D=80-N

7.80=0.05N + 0.1(80-N)
7.80=0.05N + 8 - 0.1N
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8 0
3 years ago
Please answer for question 8 and A and B
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7 0
3 years ago
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asambeis [7]

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8 0
3 years ago
For a special sale, a mens tie buyer plans to promote a $39.99 tie. Consequently, the buyer purchases 450 ties and wants to achi
zlopas [31]

Answer:

The average cost of each tie is $56.350

Step-by-step explanation:

We are given that a men tie buyer plans to promote a $39.99 tie. Consequently, the buyer purchases 450 ties

So, Cost of 450 ties = 450 \times 39.99=17995.5

An order for 100 ties that cost $20.00 each

Cost of 100 ties = 100 \times 20 = 2000

Total cost price = 17995.5+2000 = 19995.5

Let the selling price of 1 tie be x

Total ties = 450+100 = 550

So, SP of 550 ties =550x

Now we are given that markup is 55%

So, Profit % = 55%

So, CP = \frac{SP \times 100}{100+P\%}

Substitute the values

19995.5 = \frac{550x \times 100}{100+55}

19995.5 = \frac{550x \times 100}{155}

19995.5 \times 155 = 55000x

\frac{19995.5 \times 155}{55000}=x

56.350=x

Hence The average cost of each tie is $56.350

7 0
3 years ago
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