All categories

3 years ago

A heron can travel an average of 400 km in 10h. What is the rate of change of distance?

Mathematics

2 answers:

rusak2 [61]3 years ago

8 0

Answer:

40 km/h

Step-by-step explanation:

rate of change of distance = speed

speed = distance/time

speed = (400 km)/(10 h)

speed = 40 km/h

Anvisha [2.4K]3 years ago

4 0

Rate of change of distance is also known as speed.

Given,

Distance (s) = 400km = 400 × 1000m = 400,000m

Time (t) = 10h = 10 × 3600s = 36,000s

We know that,

Speed (v) = Distance/Time

$=> v = \frac{s}{t} \\ => v = \frac{400000m}{36000s} \\ => v = \frac{400m}{36s} \\ => v = \frac{100m}{9s} \\ => v = \frac{100}{9}m {s}^{ - 2} \\$

You might be interested in

Kara works at a fine jewelry store and earns commission on her total sales for the week. Her weekly paycheck was in the week tot

GrogVix [38]

Answer:

12.2%

Step-by-step explanation:

Her total paycheck minus her salary = the commission amount

6500 - 1000 = 5500

So....her commission as a percentage of sales = 5500/ 45000 = about 12.2%

3 0

3 years ago

The Knicks and Nets have a total 30 players.

Blababa [14]

Answer:

Step-by-step explanation:

From the problem statement, we can set up the following two equations:

$K + N = 30$

$20K + 10N = 500$

where $K$ is the number of Knicks players, and $N$ is the number of Nets players.

We can substitute the first equation into the second and solve for $K$

$K + N = 30$

$N = 30 - K$

$20K + 10N = 500$

$20K + 10(30 - K) = 500$

$20K + 300 - 10K = 500$

$10K + 300 = 500$

$10K = 200$

$K = 20$

5 0

3 years ago

Dan earns £224 over the course of a five-day week. How much is that per day?

alina1380 [7]

224/5= 44.8

He enrns 44.8 per day

4 0

3 years ago

Please help me!! I’ll give brainliest

Natasha2012 [34]

Answer:

the sinθ is 4√17 / 53.6

Step-by-step explanation:

All the steps are on the image :)

3 0

3 years ago

Which two values of x are roots of the polynomial below?<br> 3x2-3x+1

QveST [7]

Answer:

The roots are

$x=\frac{1}{6} [3+ i\sqrt{3}]$

$x=\frac{1}{6} [3- i\sqrt{3}]$

Step-by-step explanation:

we have

$3x^2-3x+1$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$3x^2-3x+1=0$

$a=3\\b=-3\\c=1$

substitute in the formula

$x=\frac{-(-3)\pm\sqrt{-3^{2}-4(3)(1)}} {2(3)}$

$x=\frac{3\pm\sqrt{-3}} {6}$

Remember that

$i=\sqrt{-1}$

$x=\frac{1}{6} [3\pm i\sqrt{3}]$

The roots are

$x=\frac{1}{6} [3+ i\sqrt{3}]$

$x=\frac{1}{6} [3- i\sqrt{3}]$

6 0

3 years ago