Answer:
S (1 , 0)
T (7 , 1)
Step-by-step explanation:
If QRST is a parallelogram, P is the mid point of segment QS and segment RT.
Basic formula for mid-point of segment: ((x1+x2)/2 , (y1+y2)/2)
T (x₁ , y₁) S (x₂ , y₂) P (2 , 3) Q (3 , 6) R (-3 , 5)
2 = (x₁ + (-3))/2 x₁ = 7
3 = (y₁ + 5)/2 y₁ = 1
T (7 , 1)
2 = (x₂ + 3))/2 x₂ = 1
3 = (y₂ + 6)/2 y₂ = 0
S (1 , 0)
3/5 you split something into 5 pieces than shade in 3 <span />
I don't see any diagram. So, I'll just wing it.
Value of q:
p, 6, 9 ⇒ there is a difference of 3. The sequence increases by 3. So, it can be assumed that the p is equal to 3. A(p,4) ⇒ A(3,4)
Value of q:
4, 1, q ⇒ there is a difference of 3. The sequence decreases by 3. So, it can be assumed that q is equal to -2. C(9,-2)
p q
A 3 4 ⇒ 3 + 4 = 7
B 6 1 ⇒ 6 + 1 = 7
C 9 -2 ⇒ 9 + (-2) = 7
Notice that the sequence has an equation of p + q = 7.
Answer:
y=-2x-3
Step-by-step explanation:
Since our equation is in standard form Ax+By=C we must first manipulate the equation so that we have it in the slope-intercept form such that y=mx+b. Therefore:

Therefore, our slope is 1/2 and our y-intercept is 2. Now in order to determine a perpendicular line to the one stated above we must then get the negative inverse of our slope meaning
(negative reciprocal). Now we must use the point slope formula:

Where m is the slope, x1 is -2 and y1 is 1 (because of the ordered pair given). And so:

Therefore, the line that is perpendicular to -x+2y=4 is y=-2x-3.