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2 years ago

Which of the following is a logical conclusion to the conditional statements

Mathematics

1 answer:

stellarik [79]2 years ago

7 0

Answer:

Step-by-step explanation:

If I text him now, then I will catch him before he gets home.

If I catch him before he gets home, then he will meet me in

time.

If a then b, If b then c

Combine both conditional statements by cancelling out the middle man, which is "I will catch him before he gets home."

So you get, "If i text him now, he will meet me in time"

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Two numbers have the sum of 116. The same two numbers have a difference

julsineya [31]

Answer:

64+52=116

64-52=12

Step-by-step explanation:

Brainliest plz took me like 10 minutes

4 0

2 years ago

Need answer ASAP ASAP please ASAP ASAP thank you:)

Paha777 [63]

Answer:

42°

Step-by-step explanation:

3x + 54° = 180° [Supplementary angles]

=> 3x = 180 - 54

=> 3x = 126

$= > x = \frac{126}{3}$

=> x = 42° (Ans)

5 0

3 years ago

Read 2 more answers

Find the slopes of the asymptotes of the hyperbola with the following equation.

frosja888 [35]

You are given the equation 36 = 9x² + 4y². You are asked to find the slopes of the asymptotes of the hyperbola. A hyperbola has the following general equation x²/a² + y²/b² = 1. the goal here is to find the slopes of the hyperbolic equation. So divide both sides by 36

36 = 9x² + 4y²
(1/36)[36 = 9x² + 4y²]
1 = x²/4 + y²/9
a² = 4
a = 2
and
b² = 9
b = 3

To find the slope, divide a/b and you will get 2/3.

3 0

3 years ago

Sean has some candy bars that he wants to give away. He is going to give each person 1/18 of a bar, and he has 2 3/4 to give awa

julsineya [31]

Answer:

49 people

Step-by-step explanation:

Take the amount of candy and divide by the amount in a serving

2 3/4 ÷ 1/18

Change to an improper fraction

(4*2+3)/4 ÷ 1 /18

11/4 ÷ 1/18

Copy dot flip

11/4 * 18/1

198/4

49.5

Round down since people do not want half a serving

49 people

8 0

3 years ago

The average daily jail population in the United States is 706,242. If the distribution is normal and the standard deviation is 5

Karolina [17]

a. The probability that on a randomly selected day, the jail population

is greater than 750,000 is 20.1%

b. The probability that on a randomly selected day, the jail population is

between 600,000 and 700,000 is 43.2%

Step-by-step explanation:

The given is:

1. The average daily jail population in the United States is 706,242

2. The distribution is normal and the standard deviation is 52,145

3. We need to find the probability that on a randomly selected day,

the jail population is greater than 750,000

4. We need to find the probability that on a randomly selected day,

the jail population is between 600,000 and 700,000

At first find z-score

∵ z = (x - μ)/σ, where x is the score, μ is the mean and σ is the standard

deviation

∵ x = 750,000 , μ = 706,242 and σ = 52,145

∴ z = $\frac{750,000-706,242}{52,145}$ ≅ 0.84

Use the normal distribution table of z to find the area to the right of

the z-value

∵ The corresponding area to z-score of 0.84 is 0.79955

- But we are interested in x > 750,000, we need the area to the

right of z-score

∴ P(x > 750,000) = 1 - 0.79955 = 0.2005

∴ P(x > 750,000) = 0.2005 × 100% = 20.1%

The probability that on a randomly selected day, the jail population is

greater than 750,000 is 20.1%

We will find z-score for 600,000 < x < 700,000

∵ z = $\frac{600,000-706,242}{52,145}$ ≅ -2.04

∵ z = $\frac{700,000-706,242}{52,145}$ ≅ -0.12

Use the normal distribution table of z to find the area between

the two z-values

∵ The corresponding area to z-score of -2.04 is 0.02068

∵ The corresponding area to z-score of -0.12 is 0.45224

- To find P(600,000 < x < 700,000) subtract the two values above

∴ P(600,000 < x < 700,000) = 0.45224 - 0.02068 = 0.4316

∴ P(600,000 < x < 700,000) = 0.4316 × 100% = 43.2%

The probability that on a randomly selected day, the jail population is

between 600,000 and 700,000 is 43.2%

Learn more:

You can learn more about z-score in brainly.com/question/7207785

#LearnwithBrainly

5 0

3 years ago