<span>Given: Rectangle ABCD
Prove: ∆ABD≅∆CBD
Solution:
<span> Statement Reason
</span>
ABCD is a parallelogram Rectangles are parallelograms since the definition of a parallelogram is a quadrilateral with two pairs of parallel sides.
Segment AD = Segment BC The opposite sides of a parallelogram are Segment AB = Segment CD congruent. This is a theorem about the parallelograms.
</span>∆ABD≅∆CBD SSS postulate: three sides of ΔABD is equal to the three sides of ∆CBD<span>
</span><span>Given: Rectangle ABCD
Prove: ∆ABC≅∆ADC
</span>Solution:
<span> Statement Reason
</span>
Angle A and Angle C Definition of a rectangle: A quadrilateral
are right angles with four right angles.
Angle A = Angle C Since both are right angles, they are congruent
Segment AB = Segment DC The opposite sides of a parallelogram are Segment AD = Segment BC congruent. This is a theorem about the parallelograms.
∆ABC≅∆ADC SAS postulate: two sides and included angle of ΔABC is congruent to the two sides and included angle of ∆CBD
Answer:
by 3% percent
Step-by-step explanation:
i hope this helps ._.
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2/3x-40=5/6(x+36)
multiply each side by 6 to get rid of the fraction
6* 2/3x- 6*40=6*5/6(x+36)
4x -240 = 5(x+36)
distribute
4x-240 = 5x +180
subtract 4x from each side
-240 = x +180
subtract 180 from each side
-420 =x
B
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