Combining like terms with negative coefficients 2y-3xy+4y-5xy ?
1 answer:
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The constants of a polynomial is the term that has no variable attached to it.
<h3>The constant term</h3>To determine the constant, we simply multiply the constant term in each factor of the polynomial.
So, we have:
<h3 /><h3>Polynomial P(x) = (x-2)(x-4)(x-5)</h3>Hence, the constant is -40
<h3>Polynomial P(x) = (x-2)(x-4)(x+5)</h3>Hence, the constant is 40
<h3>Polynomial P(x) =1/2(x-2)(x-4)(x+5)</h3>Hence, the constant is 20
<h3>Polynomial P(x) = 5(x-2)(x-4)(x+5)</h3>Hence, the constant is 200
<u>P(x) =-5(x-2)(x-4)(x+5)</u>
Hence, the constant is -200
Read more about polynomials at:
Answer:
y=-x+
Step-by-step explanation:
First, calculate the slope of the line that is perpendicular to the equation of line we are asked to find
m=(y2-y1)/(x2-x1)
=(2-(-4))/(-2-1)
=6/-3
=-2
in this equation the slope is 2, and to find the first equation, use y=mx+b
use the point (1, -4) to find b
-4=(2)(1)+b
-4=2+b
b=-6
the first equation of the line is y=2x-6
to find the x intercept of that line substitute 0 for y
0=2x-6
2x=6
x=3
the slope of a line perpendicular to this would be the opposite reciprocal of the slope which would be equal to -1/2
for the second equation of the line to pass thorugh the x-intercept of the first line, it must pass through (3, 0), so substitute and solve for b
y=mx+b
0=(-1/2)(3)+b
b=3/2
thus the equation of the line that is perpendicular to the line through (1,-4) and (-2, 2) and passes through the x intercept of that line is y=-x+3/2