Answer:
Han= 24 minutes
His sister= 24 minutes
His Dad= 36 minutes
Grandmother= 42 minutes
Step-by-step explanation:
Please see attached picture for full solution.
Where the working split, see the right hand side.
The question states that Han's Dad sits 1.5 times as long as both Han and his sister. There could be 2 interpretations for this:
- Dad sits for 1.5 times of (Han and his sister)
- Dad sits for 1.5 times of Han and 1.5 times of Han's sister
I've done the working for both scenarios and found out that the 1st case cannot be true since Dad would've sat for 50.4 minutes when the bus ride is only 42 minutes! Moreover, there wouldn't be enough information to know how long Han and his sister sat for.
The second case is possible and it's working is on the right.
Feel free to ask if you have any enquiries :)
<u>It's not given a scatter plot not the characteristics of the variables, but it can be safely assumed as shown below</u>
Answer:
<em>The diver's depth will be -42.9 after 30 minutes</em>
Step-by-step explanation:
The equation of the trend (or best fit line) for the scuba diver's depth in the ocean is:
y = -3.29x - 10
Where y is the diver's depth and x is the time in minutes.
To predict the diver's depth at x=30 minutes, substitute in the equation:
y = -3.29(10) - 10
y = -32.9 - 10
y = -42.9
Since no units are provided for y, the answer is:
The diver's depth will be -42.9 after 30 minutes
Answer:
They encircle the planet
times.
Step-by-step explanation:
Consider the provided information.
We have 2.5 mole of dust particles and the Avogadro's number is 
Thus, the number of dust particles is:

Diameter of a dust particles is 10μm and the circumference of earth is 40,076 km.
Convert the measurement in meters.
Diameter: 
If we line up the particles the distance they could cover is:

Circumference in meters:

Therefore,

Hence, they encircle the planet
times.

<u>Step-by-step explanation:</u>
Here we have , sin x=7/25( given sin x = 725 which is not possible ) ,
. Let's find tan (x - pi/4):
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Now , 
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 