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sp2606 [1]
2 years ago
12

3. What is the molar mass of SO2?

Mathematics
2 answers:
Arada [10]2 years ago
8 0

Answer: 64.066 g/mol

hope this helps :D

Step by Step: To find the molecular mass of SO2, you are going to want to search out the mass of SO2. The mass of sulfur is 32AMU, and also the mass of oxygen is 16AMU, then times two thanks to the subscript, so 32. Add those up, and 32+32=64AMU, which is your mass for the entire.

Natali5045456 [20]2 years ago
3 0

Answer:

64.066

Step-by-step explanation:

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Find the area of the shaded segment of the circle.
vredina [299]

Answer:

Around 5.5 square meters

Step-by-step explanation:

You can start by finding the area of the segment. Since the rest of the circle that is not in the segment is 240 degrees, the segment is 120 degrees or a third of the circle. You can therefore find the area of that segment with the formula \frac{1}{3} \pi r^2 =3\pi square meters. Now, you need to find the area of the triangle inside the sector. This is more difficult than last time, because it is not a 90 degree angle. However, you can solve this by dividing this triangle into two 30-60-90 triangles, which you know how to find the ratio of sides for. In a 30-60-90 triangle, the hypotenuse is twice the length of the smallest leg, and the larger leg is \sqrt{3} times larger than the smaller leg. In this case, these dimensions are a base of \frac{3}{2} for the smaller leg and \frac{3\sqrt{3}}{2} for the larger leg, or the base. Using the triangle area formula and multiplying by 2 (because remember, we divided the big triangle in half), you get \frac{9\sqrt{3}}{4} square meters. Subtracting this from the area of the segment, you get about 5.5 square meters. Hope this helps!

5 0
3 years ago
Use the principle of inclusion and exclusion to find the number of positive integers less than 1,000,000 that are not divisable
wel
This is a simple problem based on combinatorics which can be easily tackled by using inclusion-exclusion principle.
We are asked to find number of positive integers less than 1,000,000 that are not divisible by 6 or 4.
let n be the number of positive integers.
∴ 1≤n≤999,999
Let c₁ be the set of numbers divisible by 6 and c₂ be the set of numbers divisible by 4.
Let N(c₁) be the number of elements in set c₁ and N(c₂) be the number of elements in set c₂.

∴N(c₁) = \frac{999,999}{6} = 166666
N(c₂) = \frac{999,999}{4} = 250000
∴N(c₁c₂) = \frac{999,999}{24} = 41667
∴ Number of positive integers that are not divisible by 4 or 6,

N(c₁`c₂`) = 999,999 - (166666+250000) + 41667 = 625000
Therefore, 625000 integers are not divisible by 6 or 4
8 0
3 years ago
Least to greatest 5.08 5.8 8.05 5 8.5
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5,5.08,5.8,8.05,8.5 :))))
6 0
2 years ago
Read 2 more answers
PLZ HELP ASAP SOLID GEOMETRY
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2 years ago
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