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Advocard [28]
4 years ago
10

you have 5 question multiple choice test. Each question has four choices. you don't know any of the answers.What is the experime

ntal probability that you will guess exactly three out of five questions correctly?
Mathematics
1 answer:
Arte-miy333 [17]4 years ago
3 0
<span>To find the probability of multiple events, you must multiply the chance of one happening by the other. Since each question has 4 choices, and only one of them is right, the probability of you answering that question correctly is 1/4 The second question you answer correctly is has 1/4 probability as well. The third question you answer correctly has 1/4 probability. The fourth question (the one you get wrong) has a 3/4 chance of occurring because only 1 of the choices can be right and the other 3 are wrong. The fifth question (also the one you get wrong) has a 3/4 chance of occurring as well. So, now you have to multiple the probabilities of each question in order to find the probability of the quiz. 1/4 x 1/4 x 1/4 x 3/4 x 3/4= 0.008789063.. The probability of getting 3 answers correct out of 5 is about 0.088%

I hope I helped! :)</span>
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A study conducted by the Center for Disease Control that asked 15,000 students about
BaLLatris [955]

Answer:

The sampling distribution of \hat p is: \hat p\sim N(p,\ \frac{p(1-p)}{n}).

Step-by-step explanation:

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

\mu_{\hat p}=p

The standard deviation of this sampling distribution of sample proportion is:

\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}

The study was conducted using the data from 15,000 students.

Since the sample size is so large, i.e. <em>n</em> = 15000 > 30, the central limit theorem is applicable to approximate the sampling distribution of sample proportions.

So, the sampling distribution of \hat p is: \hat p\sim N(p,\ \frac{p(1-p)}{n}).

5 0
3 years ago
Solve the equation 4+2|3x+4|=-4
ad-work [718]

Answer:

Value of given expression x is -4

Step-by-step explanation:

Given equation in question;

4 + 2|3x + 4| = -4

Find:

Value of given expression

Computation:

4 + 2|3x + 4| = -4

Using BODMAS rule;

⇒ 4 + 2|3x + 4| = -4

⇒ 2|3x + 4| = - 4 - 4

⇒ 2|3x + 4| = - 8

⇒ |3x + 4| = - 8 / 2

⇒ |3x + 4| = - 4

⇒ 3x + 4 = - 8

⇒ 3x = -8 - 4

⇒ 3x = -12

⇒ x = -12 / 3

⇒ x = -4

Value of given expression x is -4

8 0
3 years ago
(100) points!!!! Help please
inysia [295]

Answer:

\displaystyle a_8=142,11\ mg

Step-by-step explanation:

Geometric sequence

Each term in a geometric sequence can be computed as the previous term by a constant number called the common ratio. The formula to get the term n is

\displaystyle a_n=a_1r^{n-1}

where a_1 is the first term of the sequence

The problem describes Georgie took 275 mg of the medicine for her cold in the first hour and that in each subsequent hour, the amount of medicine in her body is 91% (0.91) of the amount from the previous hour. It can be written as

amount in hour n = amount in hour n-1 * 0.91

a)

This information provides the necessary data to write the general term as

\displaystyle a_n=275\ .\ 0.91^{n-1}

b)

In the 8th hour (n=8), the remaining medicine present is Georgie's body is

\displaystyle a_n=275\ .\ 0.91^{8-1}

\displaystyle a_n=275\ .\ 0.91^{7}

\boxed{\displaystyle a_8=142,11\ mg}

6 0
3 years ago
Which of the following segments is a radius of 0?​
erastovalidia [21]
Not sure i remember this but i think radius is like half of the diameter. it’s a line from the center, to a side of the circle. in this situation, line RO would be representing the radius.

answer: D, line RO
hope this helps :)
8 0
3 years ago
Read 2 more answers
A large but sparsely populated county has two small hospitals, one at the south end of the county and one at the north end. The
Readme [11.4K]

Answer:

Step-by-step explanation:

Probability distribution of this type is a vicariate distribution because it specifies two random variable X and Y. We represent the probability X takes x and Y takes y by

f(x,y) = P((X=x,Y=y) ,

and given that the random variables are independent the joint pmf isbgiven by:

f(x,y) = fX(x) .fY(y) and this gives the table (see attachment)

(b) the required probability is given by considering X=0,1 and Y =0,1

f(x,y) = sum{(P(X ≤ 1, Y ≤ 1) }

= [0.1 +0.2 ] × [0.1 + 0.3]

= 0.3 × 0.4

= 0.12

Now we find

fX(x) = sum{[f(x.y)]} for y =0, 1 and similarly for fY(y)= sum{[f(x,y)]} for x=0, 1

fX(x) = sum{[f(x,y)]}= 0.1+0.3

= 0.4

fY(y) = sum{[f(x.y)]} = 0.1 + 0.2

= 0.3

Since fY(y) × fX(x) = 0.4 × 0.3

= 0.12

Hence f(x,y) = fX(x) .fY(y), the events are independent

(c) the required event is give by: [P(X<=1, PY<=1)]

= P(X<=1) . P(Y<=1)

= [sum{[f(x.y]} over Y=0,1] × [sum{[f(x.y)]}, over X= 0, 1

= 0.4 × 0.3

= 0.12

(d) the required event is given by the idea that: either The South has no bed and the North has or the the North has no bed and the South has. Let this event be A

A =sum[(P(X = 1<= x<= 4, Y =0)] + sum[P(X =0 Y= 1 <= x <= 3)]

A = [0.02 + 0.03 + 0.02 + 0.02] + [0.03 + 0.04 + 0.02]

A = [0.09] + [ 0.09]

A = 0.18

Pls note the sum of the vertical column X=2 is 0.3

3 0
4 years ago
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