Solve for m: 2/3=m/42

Find the surface area of the shape below. Round your answer to two decimal places.

marin [14]

The surface area of the given shape is 285.01 ft²

<h3>Surface area of a cone </h3>

From the question, we are to calculate the surface area of the given shape.

The given shape in the diagram is a cone.

The surface area of a cone is given by the formula,

$S = \pi r(r+l)$

Where S is the surface area

r is the radius

and $l$ is the slant height

First, we will calculate the slant height of the cone

$l^{2}=9^{2} +5.6^{2}$ (Pythagorean theorem)

$l^{2}=81+31.36$

$l^{2}=112.36$

$l}=\sqrt{112.36}$

$l=10.6 \ ft$

∴ The slant height is 10.6 ft

Now, for the surface area

$S = \pi \times 5.6(5.6+10.6)$
$S = \pi \times 5.6(16.2)$

$S = 90.72\pi \ ft^{2}$

$S = 285.0053 \ ft^{2}$

S ≅ 285.01 ft²

Hence, the surface area of the given shape is 285.01 ft²

Learn more on Calculating surface area of a cone here: brainly.com/question/27812847

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6 0

2 years ago

Solve (−3) ⋅ 2 please help

den301095 [7]

Answer:

-6

Step-by-step explanation:

3*2=6

so the opposite of 6 is -6

Also a negetive times a positive is always a negetive number

3 0

3 years ago

Read 2 more answers

Find the distance between the coordinates (0, 4) and (10,4) and write the result in the empty box.

barxatty [35]

The distance between the coordinates (0, 4) and (10,4) is 10

Step-by-step explanation:

We need to find the distance between the coordinates (0, 4) and (10,4)

The formula used to find distance is:

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

where

$x_1=0, y_1=4, x_2=10,y_2=4$

Putting values:

$Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\Distance=\sqrt{(10-0)^2+(4-4)^2}\\Distance=\sqrt{(10)^2+(0)^2}\\Distance=\sqrt{(10)^2}\\Distance=10$

So, The distance between the coordinates (0, 4) and (10,4) is 10

Keywords: Distance between coordinates

Learn more about Distance between coordinates at:

#learnwithBrainly

5 0

3 years ago

The swimming pool at Spring Valley High School is a rectangle with a width of 65

tatiyna

Answer:

The area of the tiled floor is given by:

area = (190m)*w + 4*w^2

Step-by-step explanation:

Remember that the area of a rectangle of length L and width W is equal to:

A = W*L

For the case of the problem, we want to find the area of the tiled floor.

Then we need to find the difference between the area of the pool including the tiled floor and the area of the pool alone.

We know that the length of the tiled floor is w.

Then if the length of the pool is 30m, the length of the pool including the tiled floor is 30m + 2*w (because we have tiles in both sides)

And if the width of the pool is 65m, then the width of the pool including the tiled floor is 65m + 2*w

Now we want to find the difference between these areas, we have:

Area of the pool alone = 65m*30m = 1950m^2

Area of the pool including the tiles = (65m + 2*w)*(30m + 2*w)

The difference is:

D = (65m + 2*w)*(30m + 2*w) - 1950m^2

D = 65m*30m + 65m*2w + 30m*2w + 4*w^2 - 1950m^2

D = (65m + 30m)*2w + 4*w^2 + (65m*30m - 1950m^2)

D = 95m*2w + 4*w^2

D = (190m)*w + 4*w^2

This is the area of the tiled floor.

4 0

3 years ago

If r= 11 units and x = 14 units, then what is the volume of the cylinder

Anastaziya [24]

Answer:

$1694 \pi$

Step-by-step explanation:

I don't see a diagram, so I'm assuming that r is the radius and x is the height of a right circular cylinder (like a soup can).

The volume of the cylinder can be found from the formula

$V=\pi (\text{radius})^2 \cdot (\text{height})$

using the variables in your problem, this is

$V=\pi r^2x$

Plug in the given values for r and x.

$V=\pi(11)^2(14) \\ V=\pi(121)(14) \\ V=1694\pi$

If you need an approximate decimal value for the volume, use a value of pi (ask your teacher how accurate it should be).

Example: Using pi = 3.1416,

$V \approx (1694)(3.1416)=5321.8704$

You might be asked to round that answer, say to 5322 cubic units.

8 0

3 years ago