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NikAS [45]
4 years ago
7

A technician is configuring a new SOHO multifunction wireless router at a customer's location to provide network access to sever

al wireless devices. The technician is required to protect the customer's private network from unauthorized access while performing the initial router setup as well as during normal operation after the configuration is completed. Which of the following is the best step for the technician to take in securing the router to meet this requirement?
Computers and Technology
1 answer:
Leno4ka [110]4 years ago
4 0

Answer:

B. Change the router's default administrative password

Explanation:

The best way to prevent any unauthorized use is to change the password to something more secure using 12 minimum characters and including number, symbols, upper and lower case.

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Fill in the blank: the final step of the dhcp discovery process is known as ______. Multiple choice, shuffle.
Ugo [173]

The configuration procedure moves into its final stage once the DHCP server has received the DHCPREQUEST message from the client. An acknowledgement packet, or DHCPACK, is sent to the client at this step.

<h3>What final step of the DHCP discovery process?</h3>

After selecting the proper IP address, the server sends the client an OFFER packet, and the client replies with a REQUEST packet. The process ends with the server sending an ACK packet to confirm that the client has received an IP address.

Therefore, DHCP may dynamically issue IP addresses to any Internet-connected device, node, or client computer.

Learn more about DHCP here:

brainly.com/question/28150867

#SPJ1

6 0
1 year ago
Non related to school but im interested,<br><br> Who here actually watches dream smp be honest
Kamila [148]
I did- but I don’t anymore
3 0
3 years ago
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In this scenario, what is the importance of anti-virus software and other similar virus protection programs?
Svetradugi [14.3K]
To protect my computer form hacking and save my files
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3 years ago
Sdq1fdszgdSHTGafeges'
kumpel [21]

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6 0
3 years ago
Create an array of numbers filled by the random number generator. (value = (int)(Math.random() * 100 + 1);) Print the array and
Y_Kistochka [10]

Answer:

Explanation:

the following is the code to run this (JAVA)

MeanStandardDev.java

import java.util.Random;

import java.util.Scanner;

public class MeanStandardDev {

public static void main(String[] args) {

// Declaring variables

int N;

double lower, upper, min, max, mean, stdDev;

/*

* Creating an Scanner class object which is used to get the inputs

* entered by the user

*/

Scanner sc = new Scanner(System.in);

// Getting the input entered by the user

System.out.print(" How many Random Numbers you want to generate :");

N = sc.nextInt();

System.out.print("Enter the Lower Limit in the Range :");

lower = sc.nextDouble();

System.out.print("Enter the Upper Limit in the Range :");

upper = sc.nextDouble();

// Creating Random class object

Random rand = new Random();

double nos[] = new double[N];

// this loop generates and populates 10 random numbers into an array

for (int i = 0; i < nos.length; i++) {

nos[i] = lower + (upper - lower) * rand.nextDouble();

}

//calling the methods

min = findMinimum(nos);

max = findMaximum(nos);

mean = calMean(nos);

stdDev = calStandardDev(nos, mean);

//Displaying the output

System.out.printf("The Minimum Number is :%.1f\n",min);

System.out.printf("The Maximum Number is :%.1f\n",max);

System.out.printf("The Mean is :%.2f\n",mean);

System.out.printf("The Standard Deviation is :%.2f\n",stdDev);

}

//This method will calculate the standard deviation

private static double calStandardDev(double[] nos, double mean) {

//Declaring local variables

double standard_deviation=0.0,variance=0.0,sum_of_squares=0.0;

/* This loop Calculating the sum of

* square of eeach element in the array

*/

for(int i=0;i<nos.length;i++)

{

/* Calculating the sum of square of

* each element in the array    

*/

sum_of_squares+=Math.pow((nos[i]-mean),2);

}

//calculating the variance of an array

variance=((double)sum_of_squares/(nos.length-1));

//calculating the standard deviation of an array

standard_deviation=Math.sqrt(variance);

return standard_deviation;

}

//This method will calculate the mean

private static double calMean(double[] nos) {

double mean = 0.0, tot = 0.0;

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Calculating the sum of all the elements in the array

tot += nos[i];

}

mean = tot / nos.length;

return mean;

}

//This method will find the Minimum element in the array

private static double findMinimum(double[] nos) {

double min = nos[0];

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Finding minimum element

if (nos[i] < min)

min = nos[i];

}

return min;

}

//This method will find the Maximum element in the array

private static double findMaximum(double[] nos) {

double max = nos[0];

// This for loop will find the minimum and maximum of an array

for (int i = 0; i < nos.length; i++) {

// Finding minimum element

if (nos[i] > max)

max = nos[i];

}

return max;

}

}

the OUTPUT should give;

How many Random Numbers you want to generate :10

Enter the Lower Limit in the Range :1.0

Enter the Upper Limit in the Range :10.0

The Minimum Number is :1.1

The Maximum Number is :9.9

The Mean is :6.30

The Standard Deviation is :2.98

cheers i hope this helps!!!

4 0
3 years ago
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