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Katena32 [7]
3 years ago
6

Question is in image attached.

Mathematics
1 answer:
Mama L [17]3 years ago
7 0

Answer:

A

Step-by-step explanation:

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What number has factors of 2 and 3 and 12 and 18 as multiples?
Firlakuza [10]
6 is the answer
 
hope this help
8 0
3 years ago
Read 2 more answers
Use the given transformation x=4u, y=3v to evaluate the integral. ∬r4x2 da, where r is the region bounded by the ellipse x216 y2
exis [7]

The Jacobian for this transformation is

J = \begin{bmatrix} x_u & x_v \\ y_u & y_v \end{bmatrix} = \begin{bmatrix} 4 & 0 \\ 0 & 3 \end{bmatrix}

with determinant |J| = 12, hence the area element becomes

dA = dx\,dy = 12 \, du\,dv

Then the integral becomes

\displaystyle \iint_{R'} 4x^2 \, dA = 768 \iint_R u^2 \, du \, dv

where R' is the unit circle,

\dfrac{x^2}{16} + \dfrac{y^2}9 = \dfrac{(4u^2)}{16} + \dfrac{(3v)^2}9 = u^2 + v^2 = 1

so that

\displaystyle 768 \iint_R u^2 \, du \, dv = 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2 \, du \, dv

Now you could evaluate the integral as-is, but it's really much easier to do if we convert to polar coordinates.

\begin{cases} u = r\cos(\theta) \\ v = r\sin(\theta) \\ u^2+v^2 = r^2\\ du\,dv = r\,dr\,d\theta\end{cases}

Then

\displaystyle 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2\,du\,dv = 768 \int_0^{2\pi} \int_0^1 (r\cos(\theta))^2 r\,dr\,d\theta \\\\ ~~~~~~~~~~~~ = 768 \left(\int_0^{2\pi} \cos^2(\theta)\,d\theta\right) \left(\int_0^1 r^3\,dr\right) = \boxed{192\pi}

3 0
2 years ago
PLEASE HELP ALMOST FINISHING ALBERA 1 PUT I NEED YOUR HELP PLEASE I BEG YOU BRAINLEST ANSWER!!!
tester [92]
59  is D 
because  with the point (-3,7) you substitute it into the equation, making it: 7=4x+b.  solve for b.  then you have y=4x+19.     work out the algebra in the possible choices and whatever equals y=4x+19 will be the answer. in this case, its D.


60 is C
same as above, you do the algebra of the equation. bring the one over after doing distribution with the 4 and voila!


61 is A
a relatively easy one, all you do is the the slope -4 where m goes, and 3 where b goes. y= -4x+3


62 is C.
this one requires more work.
chose one of the points, in this case (2,7) and put them into the equation. 
but wait, you need a slope! 
you get that use the formula (y2-y1)/(x2-x1) which will be
(7-5)/(2-3) which will be
-2.
now you have y-7= -2(x-2)
voila!



63 is  C.   y= 1/2x+3

64 is B. (3, -5)

66 is B. negative. the line  goes \ ( not / which is positive)

67 would be A. because it is positive and the I and the E are in the right places.


70 is C.  2/3.   as before, remember we can but the points into this equation and have (6-4)/(3-0) which = 2/3


71  is D.  y= 3x+10

72 is C. a third degree monomial

73 can't read


74 can't read 
 
75 can't read.

 
4 0
3 years ago
Giving brainlist to whoever answers
just olya [345]

Answer:

False

Step-by-step explanation:

V=bhw\\V=7.5*13*2\\V=195

6 0
3 years ago
Please help me solve this proof!!!!!
jolli1 [7]

statements:

1.) E is midpoint of TP

2) TP bisects MR


reasons:

1.)given

2) MT is congruent to PR       (I think)


I might be wrong though so dont count on it being right. I hope I helped. ime not that good at math. I m not BAD but yea



6 0
3 years ago
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