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Nikitich [7]
3 years ago
6

Help me again..........

Mathematics
1 answer:
DochEvi [55]3 years ago
4 0

Answer:

1. =     2. >

Step-by-step explanation:

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What is a probability ?
docker41 [41]

Answer:

A number that measures the likelihood that the event will occur.

Step-by-step explanation:

Probability is a measure of the frequency of occurrence of a phenomenon, the value of which can be expressed qualitatively or quantitatively. Probability is quantified as a real number between 0 and 1, although sometimes probability is also expressed as a percentage. The probability is 0 when the event cannot or will never happen, and the probability is 1 when it happens for sure or it always happens. If the probability is between these values, the event is not common and its occurrence is uncertain. The higher the probability value, the more common the event is or the more certain it will occur.

3 0
3 years ago
3w-17= -2 help me get the answer. An solve for w
Dominik [7]
3w=-2+17
3w=15
w=15/3
w=5
5 0
3 years ago
Read 2 more answers
Write a word problem involving fractions for which you would use the work backward strategy and addition to solve. Include solut
Delicious77 [7]
Mrs. Annie went to a store, spent half of her money and then $10 more. She went to a second store, spent half of her remaining money and then $10 more. But she then had no money left. How much money did she have to begin with when she went to the first store?
Answer: $60
7 0
3 years ago
Can someone help me with this
Helen [10]
I cant see it well try to get a better pic and i can help you 
4 0
3 years ago
How to solve this?<br>\int \frac { 4 - 3 x ^ { 2 } } { ( 3 x ^ { 2 } + 4 ) ^ { 2 } } d x​
ivanzaharov [21]

\Large \mathbb{SOLUTION:}

\begin{array}{l} \displaystyle \int \dfrac{4 - 3x^2}{(3x^2 + 4)^2} dx \\ \\ = \displaystyle \int \dfrac{4 - 3x^2}{x^2\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ = \displaystyle \int \dfrac{\dfrac{4}{x^2} - 3}{\left(3x + \dfrac{4}{x}\right)^2} dx \\ \\ \text{Let }u = 3x + \dfrac{4}{x} \implies du = \left(3 - \dfrac{4}{x^2}\right)\ dx \\ \\ \text{So the integral becomes}  \\ \\ = \displaystyle -\int \dfrac{du}{u^2} \\ \\ = -\dfrac{u^{-2 + 1}}{-2 + 1} + C \\ \\ = \dfrac{1}{u} + C \\ \\ = \dfrac{1}{3x + \dfrac{4}{x}} + C \\ \\ = \boxed{\dfrac{x}{3x^2 + 4} + C}\end{array}

5 0
3 years ago
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