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3 years ago

For a standard normal distribution which of the following variables always equals 1

Mathematics

2 answers:

Bogdan [553]3 years ago

7 0

In a normal distribution, the answer will always be 0. Furthermore is a standard of U

olchik [2.2K]3 years ago

4 0

Answer:

the answer is standard deviation or b

Step-by-step explanation:

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1. A crash repair bill comes to $1380.00. How much is 10% of

SpyIntel [72]

Answer:

1. 10% of the bill is $138. The final bill once 10% is taken off is $1242.

2. 20% of the total is $34.10. The final total once the 20% is taken off is $136.4

Step-by-step explanation:

1. A crash repair bill comes to $1380.00. How much is 10% of the bill? What is the final bill once 10% is taken off?

To find how much is 10% of the bill, we multiply the bill by 0.1

0.1*1380 = 138

10% of the bill is $138.

To find the final bill, we subtract the initial bill by 10%.

1380 - 138 = 1242

The final bill once 10% is taken off is $1242.

2. A person buys a new fan belt, a new alternator, and a new water pump for their car. The total comes to $170.50. What is 20% of the total? How much is the final total once the 20% is taken off?

Same logic as above.

0.2*170.50 = 34.1

20% of the total is $34.10.

170.50 - 34.1 = 136.4

The final total once the 20% is taken off is $136.4

8 0

2 years ago

Find the product. (−7)(8) =

Inga [223]

Answer:-56

Step-by-step explanation:The product is your answer

4 0

3 years ago

Which graph represents the system of inequalities? y+2<5x y+3x>4 y≥2x

Lostsunrise [7]

Answer:

2nd graph above the one you chose

4 0

2 years ago

How many terms are there in the sequence 1, 8, 28, 56, ..., 1 ?

BabaBlast [244]

Answer:

9 terms

Step-by-step explanation:

Given:

1, 8, 28, 56, ..., 1

Required

Determine the number of sequence

To determine the number of sequence, we need to understand how the sequence are generated

The sequence are generated using

$\left[\begin{array}{c}n&&r\end{array}\right] = \frac{n!}{(n-r)!r!}$

Where n = 8 and r = 0,1....8

When r = 0

$\left[\begin{array}{c}8&&0\end{array}\right] = \frac{8!}{(8-0)!0!} = \frac{8!}{8!0!} = 1$

When r = 1

$\left[\begin{array}{c}8&&1\end{array}\right] = \frac{8!}{(8-1)!1!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8$

When r = 2

$\left[\begin{array}{c}8&&2\end{array}\right] = \frac{8!}{(8-2)!2!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} =2 8$

When r = 3

$\left[\begin{array}{c}8&&3\end{array}\right] = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56$

When r = 4

$\left[\begin{array}{c}8&&4\end{array}\right] = \frac{8!}{(8-4)!4!} = \frac{8!}{4!3!} = \frac{8 * 7 * 6 * 5 * 4!}{4! *4*3* 2 *1} = \frac{8 * 7 * 6*5}{4*3 *2 *1} = 70$

When r = 5

$\left[\begin{array}{c}8&&5\end{array}\right] = \frac{8!}{(8-5)!5!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56$

When r = 6

$\left[\begin{array}{c}8&&6\end{array}\right] = \frac{8!}{(8-6)!6!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} = 28$

When r = 7

$\left[\begin{array}{c}8&&7\end{array}\right] = \frac{8!}{(8-7)!7!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8$

When r = 8

$\left[\begin{array}{c}8&&8\end{array}\right] = \frac{8!}{(8-8)!8!} = \frac{8!}{8!0!} = 1$

The full sequence is: 1,8,28,56,70,56,28,8,1

And the number of terms is 9

3 0

3 years ago

Some large hardware stores, such as Home Depot, boast of carrying as many as 20,000 different products in each store. This volum

Sliva [168]

Answer:

the choice of consumers regarding what to purchase to satisfy their wants and the choice of producers regarding what to produce to maximize profits.

Step-by-step explanation:

3 0

3 years ago