3.02*6.10 will give you the answer quite simple
Answer:
The statement If ∠A ≅ ∠C not prove that Δ ABD ≅ Δ CBD by SAS ⇒ C
Step-by-step explanation:
* Lets revise the cases of congruence
- SSS ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ
- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and
including angle in the 2nd Δ
- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ
≅ 2 angles and the side whose joining them in the 2nd Δ
- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles
and one side in the 2ndΔ
- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse
leg of the 2nd right angle Δ
* Lets solve the problem
- In the 2 triangles ABD , CBD
∵ AB = CB
∵ BD is a common side in the two triangles
- If AD = CD
∴ Δ ABD ≅ Δ CBD ⇒ SSS
- If BD bisects ∠ABC
∴ m∠ABD = m∠CBD
∴ Δ ABD ≅ Δ CBD ⇒ SAS
- If ∠A = ∠C
∴ Δ ABD not congruent to Δ CBD by SAS because ∠A and ∠C
not included between the congruent sides
* The statement If ∠A ≅ ∠C not prove that Δ ABD ≅ Δ CBD by SAS
Answer:
1200cm
Step-by-step explanation: this is the suface area:)
Answer:
2 hr and 58 min
Step-by-step explanation:
Answer:
The integral
is 0.
Step-by-step explanation:
A parameterization of curve C can be:
X (t) = cost 0 <= t <= pi
Y (t) = sint 0 <= t <= pi
r (t) = costi + sintj
r '(t) = -sinti + costj
![Fds = [-costsin^3t + sintcos^3t] dt](https://tex.z-dn.net/?f=Fds%20%3D%20%5B-costsin%5E3t%20%2B%20sintcos%5E3t%5D%20dt)
The integral
is given by:
![\int _0^{\pi }\left[-costsin^3t + sintcos^3t dt\right]dt](https://tex.z-dn.net/?f=%5Cint%20_0%5E%7B%5Cpi%20%7D%5Cleft%5B-costsin%5E3t%20%2B%20sintcos%5E3t%20dt%5Cright%5Ddt)
