7%, 13%, 0.15, 4/25, 21/100, 0.28
Answer:
(x, y) = (2, 1)
Step-by-step explanation:
given the 2 equations
2y - 3x = - 4 → (1)
6y + x = 8 → (2)
multiplying (2) by 3 allows the x terms to be eliminated
18y + 3x = 24 → (3)
add (1) and (3) term by term
(2y + 18y) + (- 3x + 3x) = (-4 + 24)
20y + 0 = 20 ( divide both sides by 20 )
y = 1
substitute y = 1 into either of the equations and solve for x
using (2), then
6 + x = 8 ( subtract 6 from both sides )
x = 2
solution (2, 1)
Answer:
Let x = speed for the first 96 miles
x - 9 = speed for the last 100 miles
Distance = (rate)(time), so time = (distance)/(rate)
(time for first part of trip) + (time for last part of trip) = 4 hours
So, (96)/(x) + (100)/(x - 9) = 4
Multiply both sides by the LCD (x)(x - 9) to get
96(x - 9) + 100x = 4x(x - 9)
96x - 864 +100x = 4x2 - 36x
4x2 - 232x + 864 = 0
Divide both sides by 4 to obtain x2 - 58x +216 = 0
(x - 4)(x - 54) = 0
x = 4 or x = 54
Note that x can't equal 4 because, in that case, x - 9 would be negative, so x = 54 miles per hour.
Step-by-step explanation:
ok
Answer:
y=-2/1x+5 or y=-2x+5
Step-by-step explanation:
well, you know that the equation form for this is y=mx+b, and for this the m=the slope because the lines decent is ongoing forever so it is next to the x. to count the slope, you take it from one intersection which in this case would be 5 and take it to the next which is at (1,3) and the slope would be down(or negative) 2 over(right) 1 and since the way you label it is y/x and with a normal fraction you would disregard the 1 as useless and you would take the 2 as a whole number. now for the b, B=where the line intersects a number on the Y-axis, not the x-axis, usually never is the Y-axis, which in this case would be 5, its as simple as that. have a good day ;)
my brain hurts, if anyone else answers give them brainless because my account is getting deleted in 4 hrs ;-;.
Let ????C be the positively oriented square with vertices (0,0)(0,0), (2,0)(2,0), (2,2)(2,2), (0,2)(0,2). Use Green's Theorem to
bonufazy [111]
Answer:
-48
Step-by-step explanation:
Lets call L(x,y) = 10y²x, M(x,y) = 4x²y. Green's Theorem stays that the line integral over C can be calculed by computing the double integral over the inner square of Mx - Ly. In other words
Where Mx and Ly are the partial derivates of M and L with respect to the x variable and the y variable respectively. In other words, Mx is obtained from M by derivating over the variable x treating y as constant, and Ly is obtaining derivating L over y by treateing x as constant. Hence,
- M(x,y) = 4x²y
- Mx(x,y) = 8xy
- L(x,y) = 10y²x
- Ly(x,y) = 20xy
- Mx - Ly = -12xy
Therefore, the line integral can be computed as follows
Using the linearity of the integral and Barrow's Theorem we have
As a result, the value of the double integral is -48-