Answer:
.
Step-by-step explanation:
Let , , and be constants, and let . The equation represents a parabola in a plane with vertex at .
For example, for , , , and .
A parabola is entirely above the -axis only if this parabola opens upwards, with the vertex above the -axis.
The parabola opens upwards if and only if the leading coefficient is positive: .
For the vertex to be above the -axis, the -coordinate of that point, , must be strictly positive. Thus, .
Among the choices:
- does not meet the requirements. Since , this parabola would open downwards, not upwards as required.
- does not meet the requirements. Since and is negative, the vertex of this parabola would be below the -axis.
- meet both requirements: and .
- (for which ) would touch the -axis at its vertex.
Answer:
±1/30
Step-by-step explanation:
Notice that both 16 and 14400 are perfect squares; 16 = 4² and 14400 = 120².
Thus, √(16/14400) = √(4/120)² = ±4/120 = ±1/30.
This is the set of square roots of +16/14400.
The square roots of -16/14400 are ±i(1/30) (which are imaginary roots).
A=115 and C=50.
because sum of all angles should be 180. so the x would be 32 and. ...
2.8 hours because 3.5 divided by 1.25 is 2.8
Since the equations are not shown, I believe that it could possibly be cos T = 4/17