Question

An object is thrown upward from the top of an 80​-foot building with an initial velocity of 64 feet per second. The height h of the object after t seconds is given by the quadratic equation h equals negative 16 t squared plus 64 t plus 80. When will the object hit the​ ground?

Answer 1

Answer:

Step-by-step explanation:

Solving:

Use the formula h = -16t^2 +vt +s

What we know:

v = 64 feet per second (initial velocity)

s = 80 foot (initial height)

h = ?

t ?

h = -16t^2 + 64t + 80

I know I should be asking in detail, are you allowed to use the quadratic formula or solve it by factoring it out?