An object is thrown upward from the top of an 80-foot building with an initial velocity of 64 feet per second. The height h of

Question

3 years ago

7

the object after t seconds is given by the quadratic equation h equals negative 16 t squared plus 64 t plus 80. When will the object hit the ground?

1 answer:

antoniya [11.8K] · Answer 1 · 2022-06-18T04:19:49+03:00

Answer:

Step-by-step explanation:

Solving:

Use the formula h = -16t^2 +vt +s

What we know:

v = 64 feet per second (initial velocity)

s = 80 foot (initial height)

h = ?

t ?

h = -16t^2 + 64t + 80

I know I should be asking in detail, are you allowed to use the quadratic formula or solve it by factoring it out?

An object is thrown upward from the top of an 80​-foot building with an initial velocity of 64 feet per second. The height h of