An object is thrown upward from the top of an 80-foot building with an initial velocity of 64 feet per second. The height h of
the object after t seconds is given by the quadratic equation h equals negative 16 t squared plus 64 t plus 80. When will the object hit the ground?
1 answer:
Answer:
Step-by-step explanation:
Solving:
Use the formula h = -16t^2 +vt +s
What we know:
v = 64 feet per second (initial velocity)
s = 80 foot (initial height)
h = ?
t ?
h = -16t^2 + 64t + 80
I know I should be asking in detail, are you allowed to use the quadratic formula or solve it by factoring it out?
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