Ask question

Ask question

All categories

4 years ago

13

Write a real world situation that could be represented by the system of equations Y equals 4X +10 and Y equals 3X +15

1 answer:

Nezavi [6.7K]4 years ago

4 0

Please elaborate more on your question so I can help you

You might be interested in

5. Suppose that a ball is rolling on a frictionless surface in a vacuum (no

IgorLugansk [536]

A. It will slow down and eventually stop.

4 0

3 years ago

Read 2 more answers

Solve:<br> 2y + 5x=30<br> y = 3x + 4

mafiozo [28]

Replace the second equation y=3x+4 into the first one:
2(3x+4)+5x=30
Now solve for x:
6x+8+5x=30
11x=30-8
11x=22
x=22/11
x=2
Finally, replace x=2 into y=3x+4
y=3*2+4
y=6+4 = 10
So the anwer is x=2, y=10

6 0

4 years ago

Find dy/dx for 4 - xy = y^3

storchak [24]

Answer:

$\frac{dy}{dx}=-\frac{y}{3y^2+x}$

Step-by-step explanation:

4-xy=y^3

dy/dx=?

$\frac{d(4-xy)}{dx}=\frac{d(y^3)}{dx}\\ \frac{d(4)}{dx}-\frac{d(xy)}{dx}=3y^{3-1}\frac{dy}{dx}\\ 0-(\frac{dx}{dx}y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -(1y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -(y+x\frac{dy}{dx})=3y^2\frac{dy}{dx}\\ -y-x\frac{dy}{dx}=3y^2\frac{dy}{dx}$

Solving for dy/dx: Addind x dy/dx both sides of the equation:

$-y-x\frac{dy}{dx}+x\frac{dy}{dx}=3y^2\frac{dy}{dx}+x\frac{dy}{dx} \\ -y=3y^2\frac{dy}{dx}+x\frac{dy}{dx}$

Common factor dy/dx on the right side of the equation:

$-y=(3y^2+x)\frac{dy}{dx}$

Dividing both sides of the equation by 3y^2+x:

$\frac{-y}{3y^2+x}=\frac{(3y^2+x)}{3y^2+x}\frac{dy}{dx}\\ -\frac{y}{3y^2+x}=\frac{dy}{dx}\\ \frac{dy}{dx}=-\frac{y}{3y^2+x}$

7 0

3 years ago

You and your brother are reading the same novel. You want to get ahead of him in the book, so you decide to read 30 minutes long

Sholpan [36]

Answer: its 45 if i read it right.

Step-by-step explanation:

8 0

3 years ago

If x-15=30,what is the value of 2(x 5)

Digiron [165]

X - 15 = 30
=> x = 30 + 15 = 45

2(x + 5) = 2(45 + 5) = 2(50) = 100

5 0

3 years ago