Nadine has 3 yard of ribbon to wrap birthday party favors if each favor use 1/5 yards of ribbon how many favors can nadine wrap

Mathematics

1 answer:

nata0808 [166]4 years ago

4 0

I think the answer is 15 Hope this helps

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Write the equation for the inverse of y=4arccot(

garri49 [273]

I think you meant "y = 4 arccot (x)."

This is equivalent to:

y
---- = arccot x
4

and so cot (y/4) = x

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3 years ago

15 - (-3) - 4 -16 22 -8 14

uranmaximum [27]

In this equation, you have to treat the number in the bracket first on the basis of BODMAS
15 - [-3]- 4
Note that when two minuses come together the product is a plus sign.
15 +3 - 4
You have to add before you subract
18 - 4 =14
Therefore, 15- [-3] - 4 = 14.

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4 years ago

How do I find the average rate of change?

musickatia [10]

Answer:

Step-by-step explanation:

Average rate of change is just using the slope formula: (y2-y1)/(x2-x1).

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3 years ago

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Peter takes an 8-inch by 3-inch sheet of paper and cuts from one corner of the paper to the diagonally opposite corner. now pete

tekilochka [14]

First get the length of the side the was cut (Hypotenuse).

We can use Pythagorean theorem: a^2+b^2 = c^2
a = 8, b = 3 = 1.5, c = ?

plug into forumla
8^2 + 3^2 = 73

a=8,
b=1.5,
c = sqrt( 73) or 8.5

Now add all sides together to get perimeter...
8+3+8.5 = 19.5

The perimeter of each sheet is 19.5in.

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3 years ago

Ann is adding water to a swimming pool at a constant rate. The table below shows the amount of water in the pool after different

N76 [4]

Answer:

(a) As time increases, the amount of water in the pool increases.

11 gallons per minute

(b) 65 gallons

Step-by-step explanation:

From inspection of the table, we can see that as time increases, the amount of water in the pool increases.

We are told that Ann adds water at a constant rate. Therefore, this can be modeled as a linear function.

The rate at which the water is increasing is the rate of change (which is also the slope of a linear function).

Choose 2 ordered pairs from the table:

$\textsf{let}\:(x_1,y_1)=(8, 153)$

$\textsf{let}\:(x_2,y_2)=(12,197)$

Input these into the slope formula:

$\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{197-153}{12-8}=\dfrac{44}{4}=11$

Therefore, the rate at which the water in the pool is increasing is:

11 gallons per minute

To find the amount of water that was already in the pool when Ann started adding water, we need to create a linear equation using the found slope and one of the ordered pairs with the point-slope formula:

$y-y_1=m(x-x_1)$