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jeka94
3 years ago
11

What is the absolute value of 9.8 and

Mathematics
1 answer:
Citrus2011 [14]3 years ago
7 0
The answer is -10/3 your answer
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Find the measure of the arc or angle
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2

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3 years ago
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If p and q are all positive integers and the maximum integer not greater than
garik1379 [7]

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  • 71

Step-by-step explanation:

<u>As per question we have:</u>

  • p > 0, q > 0
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3 years ago
What is the value of the expression below? 2³(3³ – 6) +4 A. 214 B. 172 C. 28 D. 200​
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8 0
3 years ago
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Describe the solutions for the quadratic equation shown below:
PtichkaEL [24]

The solutions for the quadratic equation 9x² - 6x + 5 = 0 are A. 2 complex roots

To determine the the type of roots the quadratic equation 9x² - 6x + 5 = 0, we use the quadratic formula to find the roots.

So, for a quadratic equation ax + bx + c = 0, the roots are

x = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}

With a = 9, b = -6 and c = 5, the roots of our equation are

x = \frac{-(-6) +/- \sqrt{(-6)^{2} - 4 X 9 X 5} }{2 X 9} \\x = \frac{6 +/- \sqrt{36 - 180} }{18} \\x = \frac{6 +/- \sqrt{-144} }{18} \\x = \frac{6 +/- \sqrt{-12} }{18}\\x = \frac{6}{18} +/- i\frac{12}{18} \\x = \frac{1}{3} +/- i\frac{2}{3} \\x = \frac{1 + 2i}{3}  or \frac{1 - 2i}{3}

Since the roots of the equation are (1 + 2i)/3 and (1 - 2i)/3, there are 2 complex roots.

So, the solutions for the quadratic equation 9x² - 6x + 5 = 0 are A. 2 complex roots

Learn more about quadratic equations here:

brainly.com/question/18117039

5 0
3 years ago
Is 3 a factor of 81? Use divisibility rules to explain
mixer [17]
Yes it is a factor because 31 is a factor and if u add there is a one
6 0
4 years ago
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