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3 years ago

Help and i will brainly you

Mathematics

2 answers:

kakasveta [241]3 years ago

8 0

B y=5x since the gradient is $\frac{20-0}{4-0}$

Lostsunrise [7]3 years ago

4 0

C is the right one because it has the best one and makes the most sences

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Which equation has x=4 as the solution

erma4kov [3.2K]

(1) step by step below

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3 years ago

Find - 52+3). Explain how you found your answer.

Alla [95]

Answer: -49

Step-by-step explanation:

Adding a positive number will make the negative number smaller. I am bad at explaining:(

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3 years ago

Read 2 more answers

Please help!!

inessss [21]

Answer:

2.82 seconds (3 sf)

Step-by-step explanation:

s = ut + 0.5at²

6 = -95(sin25)t + 0.5(32)t²

16t² - 40.14873487t - 6 = 0

t = 2.818501699, -0.1419193751

t is time so can't be negative.

Therefore, t = 2.82s (3 sf)

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3 years ago

Five tickets are selected at random, and those five people win a gift card. If 231 tickets were purchased for the fundraiser, ho

Arada [10]

Answer:

46.2

Step-by-step explanation:

If you divide 231 by 5 then you get that answer.

7 0

3 years ago

How do you do this question?

Ksivusya [100]

Answer:

V = (About) 22.2, Graph = First graph/Graph in the attachment

Step-by-step explanation:

Remember that in all these cases, we have a specified method to use, the washer method, disk method, and the cylindrical shell method. Keep in mind that the washer and disk method are one in the same, but I feel that the disk method is better as it avoids splitting the integral into two, and rewriting the curves. Here we will go with the disk method.

$\mathrm{V\:=\:\pi \int _a^b\left(r\right)^2dy\:},\\\mathrm{V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy}$

The plus 1 in '1 + 2/x' is shifting this graph up from where it is rotating, but the negative 1 is subtracting the area between the y-axis and the shaded region, so that when it's flipped around, it becomes a washer.

$V\:=\:\int _1^3\:\pi \left[\left(1+\frac{2}{y}\right)^2-1\right]dy,\\\\\mathrm{Take\:the\:constant\:out}:\quad \int a\cdot f\left(x\right)dx=a\cdot \int f\left(x\right)dx\\=\pi \cdot \int _1^3\left(1+\frac{2}{y}\right)^2-1dy\\\\\mathrm{Apply\:the\:Sum\:Rule}:\quad \int f\left(x\right)\pm g\left(x\right)dx=\int f\left(x\right)dx\pm \int g\left(x\right)dx\\= \pi \left(\int _1^3\left(1+\frac{2}{y}\right)^2dy-\int _1^31dy\right)\\\\$

$\int _1^3\left(1+\frac{2}{y}\right)^2dy=4\ln \left(3\right)+\frac{14}{3}, \int _1^31dy=2\\\\=> \pi \left(4\ln \left(3\right)+\frac{14}{3}-2\right)\\=> \pi \left(4\ln \left(3\right)+\frac{8}{3}\right)$

Our exact solution will be V = π(4In(3) + 8/3). In decimal form it will be about 22.2 however. Try both solution if you like, but it would be better to use 22.2. Your graph will just be a plot under the curve y = 2/x, the first graph.

5 0

3 years ago