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oksian1 [2.3K]
3 years ago
5

How far is Maine's capital city from Florida's capital city?

Mathematics
1 answer:
soldier1979 [14.2K]3 years ago
7 0

Answer:

1,650 miles

Step-by-step explanation:

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It takes a car 2.5 h to go from mile marker 15 to mile marker 130. What is the average speed of the car?
AysviL [449]

50 MPH I think tell me if im wrong.

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Which element of variation would not be affected by adding the data value 15 to the data set {3, 5, 6, 8, 9, 10, 13, 14}
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It is 13,14 because it goes up two then one one then two again which will then mess up the rotation
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3 years ago
There are 53 regular pencils in the box and some colored pencils in the box. There are a total of 84 pencils. How many colored p
vodka [1.7K]

Let be "x" the number of colored pencils in the box.

According to the information given in the exercise, there are 84 pencils in the box and 53 of them are regular pencils.

Knowing this information, you can set up the following equation:

x+53=84

Finally, you have to solve for the variable "x" in order to find its value. In order to do this, you can apply the Subtraction property of equality by subtracting 53 from both sides of the equation:

\begin{gathered} x+53-(53)=84-(53) \\ x=31 \end{gathered}

The answer is: There are 31 colored pencils in the box.

7 0
2 years ago
is it possible for a percent increase or decrease to be over 100% explain why or why not this is possible
Ivahew [28]
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3 years ago
The Copy Shop has made 20 copies of a document for you. Since the defective rate is 0.1, you think there may be some defective c
Pepsi [2]

Answer:

Binomial

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

Step-by-step explanation:

For each copy of the document, there are only two possible outcomes. Either it is defective, or it is not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem

Of the 20 copies, 2 are defective, so p = \frac{2}{20} = 0.1.

What is the probability that you will encounter neither of the defective copies among the 10 you examine?

This is P(X = 0) when n = 10.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.1)^{0}.(0.9)^{10} = 0.3487

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

8 0
4 years ago
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