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3 years ago

Given: EDF=ABF Name the postulate or theorem you can use to prove ADE=EBA.

Mathematics

1 answer:

Phoenix [80]3 years ago

4 0

The HL (hypotenuse leg) theorem states that any two right triangles that have a congruent hypotenuse and a corresponding, congruent leg are congruent triangles.

Step-by-step explanation:

AE is congruent to itself.

AB is congruent to DE

<ADE and <EBA are right angles, making them right triangles

Therefore ADE is congruent to EBA by the HL theorem.

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1. What is the value of x? Show all of your work.

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AB^2 + BC^2 = AC^2
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AB^2 + 36 = 117

Now subtract 117 from both sides
AB^2 = 81
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Answer:

Step-by-step explanation:

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3 years ago

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Find x A. 22√2 B. 22 C. 11√3/3 D. 11√3

mel-nik [20]

Answer

$22\sqrt{2}$

Step-by-step explanation:

First we gave a name to the side that is common for both triangles, can be Y for example.

Using trigonometric functions we can make a relationship between the two angles that we have and the magnitud of the side.

$sin(45)=\frac{11}{Y} \\$ , Because sin(x)= op/hip

$cos(60)=\frac{Y}{x}$ , Because con(x)=ad/hip

Having this equations, we can solve the system and find x

$Y=\frac{11}{sin(45)} \\Y=cos(60)*x$

we equal Y and solve

$\frac{11}{sin(45)}=cos(60)*x\\ x=\frac{11}{sin(45)*cos(60)} \\x=\frac{11}{\frac{\sqrt{2} }{2} *\frac{1}{2} } \\x=\frac{11}{\frac{\sqrt{2} }{4} } \\x=\frac{44}{\sqrt{2} }\\$

Then we rationalize

$x=22\sqrt{2}$

Hope you like it!

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3 years ago

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