<span>Plugging in p = 10 to solve for x:
x^2-50x-600 = (x-60)(x+10) = 0 => x = 60
x^2 - 5xp + 50p^2 = 3100
Differentiate with respect to time,
2xx' - 50x'p - 50xp' + 100pp' = 0
240 - 100(10) - 3000p' + 1000p' = 0
p' = -.38
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Answer: 0.457
multiply 3 by 7, and get 21
multiply 1 by 5, and get 5.
5 × 7 = 35.
fraction: 21/35 and 5/35
Subtract the numerators
21 − 5 = 16 = 16/35
Now we need to simplify the fraction that we have.
17 is larger than 16. So we're done reducing numbers.
<em>Our final answer: </em>
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Hope this helps!
I am joyous to assist anytime.
<em>~Jarvis</em>
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<em> </em>
Answer:
A symmetric property
Step-by-step explanation: