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3 years ago

HELP PLEASE LOOK AT THE PIC ATTACHED A PAIR OF PARALLEL LINES IS AND

Mathematics

1 answer:

Masteriza [31]3 years ago

3 0

Answer: ↓↓↓

Step-by-step explanation:

a.) DE || CB

b.) AJ ⊥ A F

c.) No, because they don't intersect at a right angle.

a. A pair of parallel lines is BC and GH.

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Birds burgers barn sold 485 hamburgers today. The number sold with cheese wise half the number sold without cheese. How many of

frez [133]

Answer:

The number of hamburgers sold with cheese was 165 and the number of hamburgers sold without cheese was 330

Step-by-step explanation:

The correct question is

Birds burgers barn sold 495 hamburgers today. The number sold with cheese wise half the number sold without cheese. How many of each kind were sold?

Let

x -----> the number of hamburgers sold with cheese

y -----> the number of hamburgers sold without cheese

we know that

$x+y=495$ -----> equation A

$x=\frac{1}{2}y$ ----> equation B

substitute the equation B in equation A and solve for y

$y+\frac{1}{2}y=495$

$\frac{3}{2}y=495$

$y=495(2)/3$

$y=330$

Find the value of x

$x=\frac{1}{2}330=165$

therefore

The number of hamburgers sold with cheese was 165 and the number of hamburgers sold without cheese was 330

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3 years ago

What are the expressions equal too 0.09x0.4

rewona [7]

0.09x0.4= 0.036 is your answer

5 0

3 years ago

Read 2 more answers

Line L has equation 2x - 3y = 5.

omeli [17]

You answer to this question is
$x = \frac{5 + 3y}{2}$

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4 years ago

Ohn, Beau, Brent, and Lance ran in a race. In how many different orders can they finish the race?

mihalych1998 [28]

Nine because there's three runners and three places to finish so 3*3=9

5 0

3 years ago

g An urn contains 150 white balls and 50 black balls. Four balls are drawn at random one at a time. Determine the probability th

xxTIMURxx [149]

Answer:

With replacement, 0.2109 = 21.09% probability that there are 2 black balls and 2 white balls in the sample.

Without replacement, 0.2116 = 21.16% probability that there are 2 black balls and 2 white balls in the sample.

Step-by-step explanation:

For sampling with replacement, we use the binomial distribution. Without replacement, we use the hypergeometric distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Sampling with replacement:

I consider a success choosing a black ball, so $p = \frac{50}{150+50} = \frac{50}{200} = 0.25$

We want 2 black balls and 2 white, 2 + 2 = 4, so $n = 4$ , and we want P(X = 2).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{4,2}.(0.25)^{2}.(0.75)^{2} = 0.2109$

With replacement, 0.2109 = 21.09% probability that there are 2 black balls and 2 white balls in the sample.

Sampling without replacement:

150 + 50 = 200 total balls, so $N = 200$

Sample of 4, so $n = 4$

50 are black, so $k = 50$

We want P(X = 2).

$P(X = 2) = h(2,200,4,50) = \frac{C_{50,2}*C_{150,2}}{C_{200,4}} = 0.2116$

Without replacement, 0.2116 = 21.16% probability that there are 2 black balls and 2 white balls in the sample.

3 0

3 years ago