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3 years ago

Please answerrree my quess

Mathematics

1 answer:

KengaRu [80]3 years ago

3 0

Answer: 2 197/1000

Explanation:

(1 3/10)^3
= (13/10)^3
= 13^3/10^3
= 2197/1000
= 2 197/1000

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Expand the following: 6(x – 4y)

Lemur [1.5K]

Answer:

6(x-4y) = 6x - 24y

Step-by-step explanation:

Here, we want to expand the given expression

We can do this using the distributive approach

We have this as;

(6 * x) - (6 * 4y)

= 6x - 24y

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2 years ago

Does this graph represent a function? <br>A=Yes <br>B=No

RSB [31]

Answer: no

Step-by-step explanation:

it doesn't pass the vertical line test

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Determine the open intervals on which the graph of f(x) = x - 4cos x is concave upward or concave downward

bazaltina [42]

The graph of the function $f(x)$ is

concave upward, when $f''(x)>0;$
concave downward, when $f''(x)$

Find $f''(x):$

$f'(x)=(x-4\cos x)'=1+4\sin x;$

$f''(x)=4\cos x.$

Now:

1. when $4\cos x>0,$ the graph of the function is concave upward and this is for

$x\in \left(-\dfrac{\pi}{2}+2\pi k,\dfrac{\pi}{2}+2\pi k\right), \text{ where } k\in Z.$

2. when $4\cos x$ the graph of the function is concave downward and this is for

$x\in \left(\dfrac{\pi}{2}+2\pi k,\dfrac{3\pi}{2}+2\pi k\right), \text{ where } k\in Z.$

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2 years ago

A new restaurant with 134 seats is being planned. Studies show that 62% of the customers demand a smoke-free area. How many se

zzz [600]

Answer: 100

Step-by-step explanation:

Given : The total number of seats planned in new restaurant =134

The percentage of customers demand a smoke-free area = 62%

It can also be written as $62\%=\dfrac{62}{100}=0.62$

The mean of this binomial distribution will be :-

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Standard deviation:-

$\sigma=\sqrt{np(1-p)}\\\\\Rightarrow\sigma=\sqrt{134(0.62)(0.38)}\approx5.6$

Now, the number of seats should be in the non-smoking area in order to be very sure of having enough seating there :-

$\mu+3\sigma=83.08+3(5.6)=99.88\approx100$

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3 years ago

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kherson [118]

The dozen is 20cents per muffin while the 4 is 21 cents per muffin

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Please answerrree my quess​

Please answerrree my quess