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3 years ago

How much was shoes and shirt before went on sale

Mathematics

1 answer:

babymother [125]3 years ago

3 0

This cannot be answered

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Find the measure of the missing angle.

LenaWriter [7]

54 degrees is the answer

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3 years ago

What is the equation of the line that passes through the point (-1, -3) and has a slope of -5?

spin [16.1K]

Answer:

Step-by-step explanation:

The point-slope form of an equation of a line:

$y-y_1=m(x-x_1)$

m - slope

(x₁, y₁) - point on a line

We have the slope m = -5, and the point (-1, -3). Substitute:

$y-(-3)=-5(x-(-1))\\\\y+3=-5(x+1)$

Convert to the slope-intercept form (y = mx + b):

$y+3=-5(x+1)$ <em>use the distributive property</em>

$y+3=-5x-5$ <em>subtract 3 from both sides</em>

$y=-5x-8$

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3 years ago

How can i use decimal models to subtract decimals??

Aleonysh [2.5K]

I think a decimal number line would help with subtracting and adding

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3 years ago

Correlation always implies causation. Is this statement correct?

svetoff [14.1K]

Answer:

Correlation does not always imply causation. (It's not correct)

Step-by-step explanation:

Correlation tests 2 variables' relationship, but just because they are related does not mean they necessarily cause each other.

3 0

3 years ago

A water storage tank has the shape of a cylinder with diameter 14 ft. It is mounted so that the circular cross-sections are vert

andrezito [222]

Answer:

percentage of the total capacity is 75.6%

Step-by-step explanation:

Hello! To solve this problem we follow the following steps

1. draw the complete scheme of the problem (see attached image)

2. To solve this problem we must find the area of the circular sector using the following equation.(c in the second attached image)

$A=\frac{R^2}{2} (\alpha -sin\alpha )$

$\alpha =2arccos(\frac{d}{R})$

3. observing the attached images we replace the values in the equations and find the area of the circular sector, remember that you must transform the angle to radians

$\alpha =2arccos(\frac{5}{7})=88.83$

$A=\frac{R^2}{2} (\alpha -sin\alpha )\\A=\frac{7^2}{2} (88.83-sen88.83)*\frac{\pi rad}{180} =37.57ft^2$

4.we calculate the area of the total circle (At), then subtract the area of the circular sector (Ac) to find the area occupied by water (Aw)

$At=\frac{\pi }{4} (14ft)^2=153.93ft^2$

Aw=At-Ac=153.93-37.57=116.36ft^2

5.Finally, we calculate the percentage that represents the water in the tank by dividing the area of the water over the total area of the tank

$\frac{116.36}{153.93} *100=75.6$

percentage of the total capacity is 75.6%

3 0

3 years ago