Complete Question
A sensor output was acquired for 32 seconds at a rate of 200 Hz and spectral analysis was performed using FFT. If the data set was split into 5 segments (each 6.4 seconds long), what is the resulting:
a)F minimum
b) F maximum
c) Frequency resolution
Answer:
a) 
b) 
c) 
Step-by-step explanation:
From the question we are told that:
Time 
Frequency
Segments 
Generally the equation for Frequency Range is mathematically given by


Therefore
a) 
b) 
c)
Generally the equation for Frequency Resolution is mathematically given by

Where
N=The Total dat points
N=Sampling Frequency *Time


Therefore


Answer:
-4 and 6
Step-by-step explanation:
sum means +
-4+6=2
difference means -4-6=10
Answer:
If the number you are rounding is followed by 5, 6, 7, 8, or 9, round the number up. If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down.
hope it helps
<em>Hi</em><em>!</em>
<em>Answer</em><em>:</em>
<em>6</em><em> </em><em>+</em><em> </em><em>(</em><em>-9</em><em>)</em><em> </em><em>-</em><em> </em><em>(</em><em>-4</em><em>)</em><em> </em><em>-</em><em> </em><em>3</em><em> </em><em>=</em>
<em>=</em><em> </em><em>6</em><em> </em><em>-</em><em> </em><em>9</em><em> </em><em>-</em><em> </em><em>b</em><em> </em><em>(</em><em>-4</em><em>)</em><em> </em><em>-</em><em> </em><em>3</em>
<em>=</em><em> </em><em>6</em><em> </em><em>-</em><em> </em><em>9</em><em> </em><em>+</em><em> </em><em>4b</em><em> </em><em>-</em><em> </em><em>3</em>
<em>=</em><em> </em><em>-6</em><em> </em><em>+</em><em> </em><em>4b</em>
<em>=</em><em> </em><em>4b</em><em> </em><em>-</em><em> </em><em>6</em>
<em>I hope I helped you! Good luck at school! </em>
Hello!
First you have to find the total amount of kids
5 kids a table
28 tables
Multiply these numbers
28 * 5 = 140
Then divide by the amount of kids in a class
140 / 35 = 4
The answer is 4 classes
Hope this helps!