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3 years ago

I need help with this question plz!! Geometry best gets brainliest

Mathematics

1 answer:

777dan777 [17]3 years ago

6 0

Answer:

Step-by-step explanation:

Is this rsm??

Just wanted to see because I have that problem too

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2/3+q=1/2 what is Q

JulsSmile [24]

Q=rational number=1/6

2/3+q=1/2=1/6

4 0

3 years ago

Simplify negative 9 over 6 divided by 3 over negative 2..

34kurt

-6/3 division sign 2/-9

To solve: multiply by reciprocal inverse

-6/3 x -9/2= 54/6 or 9

6 0

3 years ago

Which trigonometric functions are negative in the fourth (IV) quadrant?

anzhelika [568]

<h3>Answers are: sine, tangent, cosecant, cotangent</h3>

Explanation:

On the unit circle we have some point (x,y) such that x = cos(theta) and y = sin(theta). The sine corresponds to the y coordinate of the point on the circle. Quadrant IV is below the x axis which explains why sine is negative here, since y < 0 here.

Since sine is negative, so is cosecant as this is the reciprocal of sine

csc = 1/sin

In quadrant IV, cosine is positive as x > 0 here. So the ratio tan = sin/cos is going to be negative. We have a negative over a positive when we divide.

Because tangent is negative, so is cotangent.

The only positive functions in Q4 are cosine and secant, which is because sec = 1/cos.

7 0

3 years ago

Dr. Seals borrows $15,000 to remodel her backyard. The interest rate is 3%. The interest is compounded twice a year for two year

ahrayia [7]

Answer:

$1688.26

interest= $188.26

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

One number is 4 more than another. the difference between their squares is 64. what are the numbers

lora16 [44]

We have to set up 2 different equations if we are to solve for 2 unknowns. The first equation is x = y + 4. One number (x) is (=) 4 more than another (y + 4). Since we have determined that x is larger (cuz it's 4 more than y), when we set up their difference, we are going to subtract y from x cuz x is bigger. The second equation then is $x^{2} - y^{2} =64$ . In our first equation we said that x = y + 4, so let's sub that value in for x in the second equation: $(y+4) ^{2} - y^{2} =64$ . Expand that binomial to get $y^{2} +8y+16- y^{2} =64$ . Of course the y squared terms cancel each other out leaving us with 8y + 16 = 64. Solving for y we get that y = 6. Subbing 6 in for y in our first equation, x = 6 + 4 tells us that x = 10. Yay!

5 0

3 years ago