Starting from what I know (the difference between ribbons), I decided to go from the bottom and work my way up. I then noticed a pattern (each sum was three more of the previous one), and decided to keep my pattern of the three numbers but not have to do any major mental work and instead add three to the previous sum until I got to 38.
Answer:
43cm²
Step-by-step explanation:
let's first consider the area of a square.
the area is L² which means all sides are equal so we take the length times the breadth which is both equal because like we said all sides are equal.
so to find the side of the square using the area, we take the square root of both of the area.
and also
so we have the height of the triangle as 5cm and the base is 4.2cm.
now, from the triangle, since we have two sides and it's a right-angled, we can use Pythagoras' formula.
so the side 6.53cm is also the same side as the largest triangle. Since it's a square, all sides are equal. So we find the area of the largest triangle by using the formula
Area = L²
Area = 6.53²
Area = 42.6cm
the nearest cm square
Area = 43cm²
That is, log x = k if and only if 10 k = x.
The answer would be j<14
Because Sophie is 14 and hake is any number younger then her
In the smaller triangle, let be the length of the smallest leg. Then the smallest leg in the larger triangle is .
Within the scope of the smaller triangle, we have such that
Then within the larger the triangle, we would have
Now we can solve for :