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s344n2d4d5 [400]
3 years ago
3

Functions 1 and 2 are shown below.. Function 1: f(x) = -4x2 + 6x + 3. Which function has a larger maximum? Type your answer as 1

or 2.
Mathematics
2 answers:
DanielleElmas [232]3 years ago
8 0
Function 1:
x = - b/ 2 a = 6 /8 = 3/4
f ( 3/4 ) = - 4 * 9/16 + 6 * 3/4 + 3 = - 9 /4 + 18 / 4 + 3 = 2.75 + 3 = 5.25
y max = 5.25
Function 2:
y max = 3 ( from a picture )
The 1st function has a larger maximum  ( 5.25 > 3 )
Answer:  1
andreev551 [17]3 years ago
8 0

Answer:

Function 1 has a larger maximum

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PLZ HELP!<br>dont just answer something random for points:)tysm​
sergiy2304 [10]

Answer:

4(x^{2} -4)^{2} -76

Step-by-step explanation:

Take out 4:

4(x^2-8x)-12

=4(x^2-8x+16-16)-12

=4(x^2-8x+16)-64-12

=4(x^2-4)^2 - 76

=4(x^{2} -4)^{2} -76

6 0
3 years ago
If f(x)= -2x²-,find f(0).​
IRINA_888 [86]

Answer:

0

Step-by-step explanation:

f(0) = -2(0)²

= -2(0)

= 0

6 0
4 years ago
Not sure how to do this. Help is much appreciated. :D
Free_Kalibri [48]

Answer:

m = √n/3 -k

Step-by-step explanation:

√n = 3(k + m)

=> √n/3 = k + m

∴ m = √n/3 -k

Hope this helps!!

6 0
3 years ago
Which of the expressions below has a 4 in the ones place of the sum? Select all that apply.
lara [203]

Answer:

its C or D

Step-by-step explanation:

i think it's both !

8 0
3 years ago
Read 2 more answers
Use a matrix to solve the system:
Romashka-Z-Leto [24]

Answer:

(2.83 , 1 , 4)

Step-by-step explanation:

2x+2y-z=4\\4x-2y-2z=2\\3x+3y-4z=-4\\

Rewrite these equations in matrix form

\left[\begin{array}{ccc}2&2&-1\\4&-2&-2\\3&3&-4\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{ccc}4\\2\\-4\end{array}\right] \\

we can write it like this,

AX=B\\X=A^{-1}B

so to solve it we need to take the inverse of the 3 x 3 matrix A then multiply it by B.

We get the inverse of matrix A,

A^{-1}=\left[\begin{array}{ccc}7/15&1/6&-1/5\\1/3&-1/6&0\\3/5&0&-2/5\end{array}\right]  \\

now multiply the matrix with B

X=A^{-1}B\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}7/15&1/6&-1/5\\1/3&-1/6&0\\3/5&0&-2/5\end{array}\right]\left[\begin{array}{ccc}4\\2\\-4\end{array}\right] \\\\\\\left[\begin{array}{ccc}x\\y\\z\end{array}\right] =\left[\begin{array}{ccc}2.83\\1\\4\end{array}\right] \\

4 0
3 years ago
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