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MariettaO [177]
2 years ago
11

Not sure how to do this. Help is much appreciated. :D

Mathematics
1 answer:
Free_Kalibri [48]2 years ago
6 0

Answer:

m = √n/3 -k

Step-by-step explanation:

√n = 3(k + m)

=> √n/3 = k + m

∴ m = √n/3 -k

Hope this helps!!

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5/6x6/7=?? Please answer
Lapatulllka [165]

\red { \orange {\boxed {\boxed{Answer}}}}

<h2>=  \frac{5}{6}  \times  \frac{6}{7}</h2><h2>=  \frac{5 \times 6}{6 \times 7}</h2><h2>=  \frac{30}{42}</h2><h2>=  \frac{30 \div 6}{42 \div 6}</h2><h2>=  \frac{5}{7}</h2>

#IfWrongPleaseReport

#StudyTogetherWithMe

#ILoveMath

6 0
3 years ago
What is the instantaneous rate of change of f(x)=xe^x-(x 2)e^(x-1) at x=0 ?
lozanna [386]
You have to derive for a multiplication in both terms:
=e^x+xe^x-(e^x-1 + (x-2)e^x-1) now apply distributive property in the last term:
=e^x+xe^x+e^x-1-xe^x-1   now replace each x by 0 (x=0)
=1 + 0 + e^-1 + 0 = 1+ e^-1 = 1.3679
8 0
3 years ago
Suppose it is known that the distribution of purchase amounts by customers entering a popular retail store is approximately norm
iragen [17]

Answer:

a. 0.691

b. 0.382

c. 0.933

d. $88.490

e. $58.168

f. 5th percentile: $42.103

95th percentile: $107.897

Step-by-step explanation:

We have, for the purchase amounts by customers, a normal distribution with mean $75 and standard deviation of $20.

a. This can be calculated using the z-score:

z=\dfrac{X-\mu}{\sigma}=\dfrac{85-75}{20}=\dfrac{10}{20}=0.5\\\\\\P(X

The probability that a randomly selected customer spends less than $85 at this store is 0.691.

b. We have to calculate the z-scores for both values:

z_1=\dfrac{X_1-\mu}{\sigma}=\dfrac{65-75}{20}=\dfrac{-10}{20}=-0.5\\\\\\z_2=\dfrac{X_2-\mu}{\sigma}=\dfrac{85-75}{20}=\dfrac{10}{20}=0.5\\\\\\\\P(65

The probability that a randomly selected customer spends between $65 and $85 at this store is 0.382.

c. We recalculate the z-score for X=45.

z=\dfrac{X-\mu}{\sigma}=\dfrac{45-75}{20}=\dfrac{-30}{20}=-1.5\\\\\\P(X>45)=P(z>-1.5)=0.933

The probability that a randomly selected customer spends more than $45 at this store is 0.933.

d. In this case, first we have to calculate the z-score that satisfies P(z<z*)=0.75, and then calculate the X* that corresponds to that z-score z*.

Looking in a standard normal distribution table, we have that:

P(z

Then, we can calculate X as:

X^*=\mu+z^*\cdot\sigma=75+0.67449\cdot 20=75+13.4898=88.490

75% of the customers will not spend more than $88.49.

e. In this case, first we have to calculate the z-score that satisfies P(z>z*)=0.8, and then calculate the X* that corresponds to that z-score z*.

Looking in a standard normal distribution table, we have that:

P(z>-0.84162)=0.80

Then, we can calculate X as:

X^*=\mu+z^*\cdot\sigma=75+(-0.84162)\cdot 20=75-16.8324=58.168

80% of the customers will spend more than $58.17.

f. We have to calculate the two points that are equidistant from the mean such that 90% of all customer purchases are between these values.

In terms of the z-score, we can express this as:

P(|z|

The value for z* is ±1.64485.

We can now calculate the values for X as:

X_1=\mu+z_1\cdot\sigma=75+(-1.64485)\cdot 20=75-32.897=42.103\\\\\\X_2=\mu+z_2\cdot\sigma=75+1.64485\cdot 20=75+32.897=107.897

5th percentile: $42.103

95th percentile: $107.897

5 0
3 years ago
Pls help me and thank youuu
nlexa [21]

Answer:

x = 1

Step-by-step explanation:

14 -4x = 10

-4x = -4

x = 1

4 0
2 years ago
Read 2 more answers
By October 19th, Gordon had read 35 pages. Starting on October 20th, he decides to read the same number of pages each day until
PilotLPTM [1.2K]
Gordon read a total of 35 pages, so if there is p pages read per day and 10 days you'd have something that looks like this: 35 = 10p.

8 0
3 years ago
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