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2 years ago

Not sure how to do this. Help is much appreciated. :D

Mathematics

1 answer:

Free_Kalibri [48]2 years ago

6 0

Answer:

m = √n/3 -k

Step-by-step explanation:

√n = 3(k + m)

=> √n/3 = k + m

∴ m = √n/3 -k

Hope this helps!!

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What would you expect the nominal rate of interest to be if the real rate is 4.4 percent and the expected inflation rate is 7.5

ANTONII [103]

Answer:

Nominal Interest rate=11.9%

Step-by-step explanations:

The Fisher effect is a theory propounded by an economist named Irving Fisher.

Fisher's equation shows the relationship between real Interest rate, expected inflation rate and nominal Interest rate.

It can be calculated by subtracting the expected inflation rate from the nominal Interest rate to give the real Interest rate.

Real Interest rate= nominal Interest rate - expected inflation rate

Given,

Real Interest rate= 4.4%=0.044

Expected inflation rate=7.5%=0.075

Nominal Interest rate=?

Therefore,

Real Interest rate=nominal Interest rate - expected inflation rate

Nominal Interest rate=Real Interest rate+expected inflation rate

Nominal Interest rate=0.044+0.075

Nominal Interest rate=0.119

Nominal Interest rate=11.9%

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3 years ago

Newton's law of cooling is:

Mnenie [13.5K]

Answer:

$t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr$

So it would takes approximately 6.9 hours to reach 32 F.

Step-by-step explanation:

For this case we have the following differential equationÑ

$\frac{du}{dt}= -k (u-T)$

We can reorder the expression like this:

$\frac{du}{u-T} = -k dt$

We can use the substitution $w = u-T$ and $dw =du$ so then we have:

$\frac{dw}{w} =-k dt$

IF we integrate both sides we got:

$ln |w| = -kt +C$

If we apply exponential in both sides we got:

$w = e^{-kt} *e^c$

And if we replace w = u-T we got:

$u(t)= T + C_1 e^{-kt}$

We can also express the solution in the following terms:

$u(t) = (T_i -T_{amb}) e^{kt} +T_{amb}$

For this case we know that $k =-0.15 hr$ since w ehave a cooloing, $T_{i}= 70 F, T_{amb}=11F$ , we have this model:

$u(t) = (70-11) e^{-0.15t} +11$

And if we want that the temperature would be 32F we can solve for t like this:

$32 = 59 e^{-0.15 t} +11$

$21=59 e^{-0.15 t}$

$\frac{21}{59} = e^{-0.15 t}$

If we apply natural logs on both sides we got:

$ln (\frac{21}{59}) =-0.15 t$

$t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr$

So it would takes approximately 6.9 hours to reach 32 F.

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3 years ago

One car costs $18,942.

oksian1 [2.3K]

Answer:

28,130

Step-by-step explanation:

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2 years ago

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Pretty easy math equation I think but I forgot how to solve it look at picture

GrogVix [38]

X = 32 because 100 / 4 is 25, which would make the numerator for x 32

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Answer:

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Step-by-step explanation:

295.99 - 30% ...........

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