3 years ago

What is the value of the expression below when a = 3 and b = 7?

Mathematics

2 answers:

Alexandra [31]3 years ago

8 0

The answer is 42 I think

svp [43]3 years ago

6 0

Answer:

Step-by-step explanation:

9^2*7-2*7

56-14

I hope this helps.

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Helppppp me please this is so hard

Amiraneli [1.4K]

Answer:

B, C and E

Step-by-step explanation:

A) 4x + 15 < -21

4x < -36

x < -9

=> No

B) -5/3x + 17/3 < 9

-5x + 17 < 27

-5x < 10

x > -2

=> Yes

C) 1/4x - 16 > -18

1/4x > -2

x > -8

=> Yes

D) -3/2x - 11/4 ≥ 31/4

-3/2x ≥ 42/4

-3/2x ≥ 21/2

x ≤ -7

=> No

E) -8/3x + 5 ≤ 9

-8/3x ≤ 4

x ≥ -4 x 3/8

x ≥ -3/2

=> Yes

6 0

3 years ago

Read 2 more answers

George bought 30 packets of football cards they were 14 cards and each packet how many cards did George buy

Sergeeva-Olga [200]

420!!!!!!!!!!!!!!!!!!!!!

4 0

3 years ago

Each month Allison gets a $15 allowance and earns $100 working at the theater. She uses the expression 15x+100y to keep track of

Marizza181 [45]

Step-by-step explanation:

The expression for he earning of Allison and her allowance is as follows :

15x+100y

Part A

Variables are x and y. Coefficients are 15 and 100.

Part (B)

There are two terms in this expression. + is used to separate the terms. 15x and 100y are the terms.

Part (C) As $15 shows her earning from allowances. Hence, 15x shows allowance.

3 0

4 years ago

PLZ help super fast thanks

Nikolay [14]

Answer:

B. $\frac{1}{x^2y^7}$

Step-by-step explanation:

Given:

$(x^3y^{-2}z)(x^{-5}y^{-5}z^{-1})$

Hence Solving the given expression we get;

By Law of Indices which states;

$(a^xb^yc^z)(a^pb^qc^r) = a^{x+p}b^{y+q}c^{z+r}$

Hence we get;

$x^{3+(-5)}y^{(-2)+(-5)}z^{1+(-1)}\\\\x^{3-5}y^{-2-5}z^{1-1}\\\\x^{-2}y^{-7}$

Also We know that

$a^{-6} =\frac{1}{a^6}$

So,

$\frac{1}{x^2y^7}$

8 0

3 years ago

Marco has 2 bags of flour with 6 2/3 cups of flour in each bag. He makes 6 batches of muffins and uses 1 2/3 cups of flour for e

bija089 [108]

Answer:what did you get

Step-by-step explanation:

8 0

3 years ago