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asambeis [7]
3 years ago
5

Please help me with i ii iii Step by step

Mathematics
2 answers:
viva [34]3 years ago
8 0
.3 (15x+9)/3
(15x/3)+(9/3)
5x+(9/3)
5x+3
1. 4(3x+2y)-5(3x+4y)
12x+8y-5(3x+4y)
12x+8y-15x-20y
-3x+8y-20y
-3x-12y
-3(x+4y)
2. 3k+3m-2-6k-3m-2n
-3k+3m-2-3m-2n
-3k-2n-2
UkoKoshka [18]3 years ago
7 0

(i) I used distributive property to get the x’s and y’s out of parentheses. I then combined like-terms to simplify until I could do no more. That is your final answer for (i) is -3x - 12y

(ii) This one is similar to the first one, just with no parentheses. I combined like terms again until not like terms were left. Your final answer for (ii) is -3k -2 -2n

(iii) I started by dividing 15 by 3 and got 5, and because the 15 had an x to it, you get 5x. I then moved onto the next term, 9. 9 divided by 3, to get 3. Your final answer for (iii) is 5x + 3

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20% if you have 100 apples and put them in groups of five there will be 20 in each bunch
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Ludovica creates flash cards for her vocabulary words.She creates 3 more cards per noun.
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Answer: what is the whole question angel?


Step-by-step explanation:


7 0
3 years ago
A class has 35 students, of which 16 are male and 19 are female. If 6 of the students are selected at random to form a committee
madreJ [45]

Answer:

The probability of choosing exactly 2 male and 4 female students =\frac{\binom{16}{2}\times \binom{19}{4}}{\binom{35}{6}}

Step-by-step explanation:

We are given that a class has 35 students

Number of male=16

Number of female=19

We have to choose 6 students for committee

We have to find the probability that exactly 2 male students are selected

Probability=P(E)=\frac{number\;of\;favorable\;cases}{total\;number\;of\;cases}

If we have to choose total 6 student in which 2 male and 4 female

Combination formula:

nC_r=\frac{n!}{r!(n-r)!}

Using the formula

The probability of choosing exactly 2 male and 4 female students =\frac{\binom{16}{2}\times \binom{19}{4}}{\binom{35}{6}}

5 0
3 years ago
What is the volume of this prism 10mm 8mm 12mm 3mm 2mm
Solnce55 [7]

Answer:

5760 mm

Step-by-step explanation:

just multiply lol

3 0
2 years ago
Point E is the midpoint of AB and point F is the midpoint
GREYUIT [131]

The options are;

1) AB is bisected by CD

2) CD is bisected by AB

3) AE = 1/2 AB

4) EF = 1/2 ED

5) FD= EB

6) CE + EF = FD

Answer:

Options 1, 3 & 6 are correct

Step-by-step explanation:

We are told that Point E is the midpoint of AB. Thus, any line that passes through point E will bisect AB into two equal parts.

The only line passing through point E is line CD.

Thus, we can say that line AB is bisected by pine CD. - - - (1)

Also, since E is midpoint of Line AB, it means that;

AE = EB

Thus, AE = EB = ½AB - - - (2)

Also, we are told that F is the mid-point of CD.

Thus;

CF = FD

Point E lies between C and F.

Thus;

CE + EF = CF

Since CF =FD

Thus;

CE + EF = FD - - - (3)

5 0
3 years ago
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