Using the expected value of a discrete distribution, it is found that:
a) His expected value is of -$2.5.
b) The fair price of a ticket is of $0.5.
<h3>What is the mean of a discrete distribution?</h3>
The expected value of a discrete distribution is given by the <u>sum of each outcome multiplied by it's respective probability</u>.
In this problem, the distribution for the net value of the ticket is:
Item a:
The expected value is given by:
His expected value is of -$2.5.
Item b:
With an unknown ticket price, the distribution is:
The game is fair if E(X) = 0, hence:
0.5 - x = 0
x = 0.
The fair price of a ticket is of $0.5.
More can be learned about the expected value of a discrete distribution at brainly.com/question/24855677
When the product of two integers is a positive number, you either kept all positives after multiplying or multiplied a negative and a vegative.
When the product of two integers is a negative number, you multiplied a negative and a positive.
Answer:
21/99 or 7/33
Step-by-step explanation:
x = 0.212121
Then we multiple the decimal and x by hundred.
100x = 21.212121
Then we subtract the 21.212121 by 0.212121.
100x = 21.212121 - 0.212121
But when you are subtracting 100x, you need to subtract 100x by x because in the first step it said x = 0.212121.
100x - x = 21.212121 - 0.212121
You will have at the end is
99x = 21
Divide 99 on both side and you left with
21/99 or 7/33 simplified version
9, 18, 27 You do this by multiplying nine by the first three numbers: 1,2,3