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MakcuM [25]
3 years ago
11

Can someone please solve this?I'm stuck and I don't know how​

Mathematics
2 answers:
VARVARA [1.3K]3 years ago
6 0

Answer:

D

Step-by-step explanation:

If im inncorect you can check this with "Mathaway"

guapka [62]3 years ago
4 0

Answer: D

Hope this helps!

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In two or three sentences explain how you would solve for the real solutions of the following equation: please help asap!!
g100num [7]

the real solutions for the equation x^{3}=-64 are -

x=4,2+-2\sqrt{3i}

Step-by-step explanation:

   x^{3} = - 64

   x^{3} +64  = 0

   We can write 64 as  4^{3}

  x^{3} + 4^{3} = 0

  using the identity  ( x^{3}+y^{3} = (x+y)(x^{2} -xy+y^{2} ) )

we get,

  = (x+4) (x^{2} -x*4+4^{2} )

  = (x+4)(x^{2} -4x+16)    ....................(1)

 solving the quadratic equation  ,

   x^{2} -4x+16 =0

solutions of this quadratic equation can be obtained by

   x=-b +- \sqrt{b^{2}-4ac } /2a

let use y for factors

x=-(-4x)+-\sqrt{(-4x^{2} )-4*x^{2} *16}  / 2*x^{2}

x=4x+-\sqrt{16x^{2} -64x^{2} } /2x^{2}

x=4+-\sqrt{16-64}/2

x=4+-4\sqrt{3i} /2

<u />x=2+-2\sqrt{3i}    ..................(2)

from the equation 1 we have,

x-4=0

which gives solution x=4

and from equation 2 we got  x=2+-2\sqrt{3i}

so the real solutions for the equation x^{3}=-64 are -

x=4,2+-2\sqrt{3i}

3 0
3 years ago
A sequence is defined by the function f ( n ) = f ( n − 1 ) + 5 , where n represents the number of the term for n &gt; 1 , and f
Shkiper50 [21]

Step-by-step explanation:

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6 0
3 years ago
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80+x+45+2x+55=180

3x+100+80=180

3x=0

X=0

Measure of angle a=45

8 0
3 years ago
What is cosine ? I really need this answer for my test tomorrow. Please help
Kisachek [45]
Cosine is \frac{adjacent}{hypotenuse} which applies to a right triangle. I hope that helps you.
3 0
3 years ago
Read 2 more answers
Quadrilateral ABCD is a square. if m
olganol [36]
The answer is B. 18

Explanation:

We know that a square has 4 right angles. A right angle is 90°.

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4 0
3 years ago
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