No, when you have a zero in that space you don't necessarily need an addendum unless it helps you.
Answer:
the probability is 2/9
Step-by-step explanation:
Assuming the coins are randomly selected, the probability of pulling a dime first is the number of dimes (4) divided by the total number of coins (10).
p(dime first) = 4/10 = 2/5
Then, having drawn a dime, there are 9 coins left, of which 5 are nickels. The probability of randomly choosing a nickel is 5/9.
The joint probability of these two events occurring sequentially is the product of their probabilities:
p(dime then nickel) = (2/5)×(5/9) = 2/9
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<em>Alternate solution</em>
You can go at this another way. You can list all the pairs of coins that can be drawn. There are 90 of them: 10 first coins and, for each of those, 9 coins that can be chosen second. Of these 90 possibilities, there are 4 dimes that can be chosen first, and 5 nickels that can be chosen second, for a total of 20 possible dime-nickel choices out of the 90 total possible outcomes.
p(dime/nickel) = 20/90 = 2/9
A. 1.50c+ 4.00a = 5050 (Money earned)
c + a =2200 (Guests in the museum)
Amount charged for downloading individual songs = x dollars
Amount charged for downloading an entire song album = y dollars
Person A:
6x + 2y = 25.92
3x + y = 12.96
y = 12.96 - 3x
Person B:
4x + 3y = 33.93
Putting the value of y from the first equation in the second we get
x = 0.99 dollars
Putting the value of x in the first equation we get
y = 12.96 - 3x
= 12.96 - 2.97
= 9.99 dollars
Answer:
-60x + 10
Step-by-step explanation:
-5 x 2(6x - 1)
-10 (6x - 1)
-60x + 10
